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Juliette [100K]

3 years ago

5

Write an equation in slope intercept form for the line that passes through a given point in your Parallel to the graph the given

equation (3,2) y=x+5

1 answer:

bearhunter [10]3 years ago

4 0

See attached photo for solution

please give a thanks or brainliest if you found my answer helpful :)

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The rise and span for a roof are shown. The pitch of a roof is the ratio of the rise to the half-span. If the rise is 8 feet and

Effectus [21]

<span>Half-span is half of span. Pitch of the roof is calculated as rise/(span/2). In this case, rise is 8 feet and span is 30 feet. So, the pitch can be calculated as 8/(30/2) or 8/15. Pitch is normally represented as the number of inches of rise per foot. So, to reduce 8/15 to match a foot, we multiply it by 12. So, (8/15) * 12 gives us 6.4 inches of rise per foot.</span>

3 0

3 years ago

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Dom Grady has completed 21 out of 25 passes for his football team. What percentage of his total passes has he completed? Explain

BabaBlast [244]

Answer:

84%

Step-by-step explanation:

Completed passes: 21

total: 25

fraction: 21/25

21/25 x100

= 84

He has completed 84% of passes.

7 0

3 years ago

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What is the andwer???

djverab [1.8K]

Answer:

3 and 11

Step-by-step explanation:

Given 2 sides with third side x , then

difference of 2 sides < x < sum of 2 sides , that is

7 - 4 < x < 7 + 4

3 < x < 11

Thus the possible values the third side cannot be are 3 and 11

4 0

3 years ago

At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?

Neporo4naja [7]

Every body has two hands so we have to multiply 66 by 2.

66 multiplied by 2 is equal to 132

The answer is 132.

hope it helps.

Can you choose mine as the brainliest answer <u><em>please please?</em></u>

4 0

3 years ago

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The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

STatiana [176]

Answer:

24761 mosquitoes

5.4 days

Step-by-step explanation:

Let the equation that shows the population of the mosquitoes after x days,

$A=P(1+r)^x$

Where,

P = Initial population,

r = rate of increasing per day,

Here, A = 1000, when x = 0,

$1000=P(1+r)^0\implies P = 1000$

A = 1900 when x = 1,

$1900 = P(1+r)^1\implies 1900 = 1000(1+r)\implies 1.9 = 1 + r\implies r = 0.9$

Thus, the required function that represents the population after x days,

$A=1900(1+0.9)^x=1900(1.9)^x$

If x = 4,

The number of mosquito after 4 days,

$A=1900(1.9)^4 = 24760.99\approx 24761$

If A = 60,000,

$60000 = 1900(1.9)^x$

$\frac{600}{19}=1.9^x$

Taking log both sides,

$\log(\frac{600}{19})=x\log 1.9$

$\implies x = \frac{\log(\frac{600}{19})}{\log 1.9}=5.378\approx 5.4$

Thus, there will 60,000 mosquitoes after 5 days.

6 0

3 years ago