All categories

1 year ago

A building in a city has a rectangular base. The length of the base measures 75 ft less than three times the width. The

Mathematics

1 answer:

MariettaO [177]1 year ago

7 0

The dimensions of the rectangular base of the building with the given perimeter are 120ft and 285ft.

<h3>What are the dimensions of the rectangle base?</h3>

The perimeter of rectangle is expressed as;

P = 2( l + w )

Given the data in the question;

Let x represent the width of the rectangular base.

Width w = x
Length = l = 3x-75
Perimeter P = 810ft

Plug these values into the equation above.

P = 2( l + w )

810 = 2( (3x-75) + x )

810 = 6x - 150 + 2x

810 = 8x - 150

8x = 810 + 150

8x = 960

x = 960/8

x = 120

Hence,

Width of the rectangle = x = 120ft

Length of the rectangle = 3x-75 = 3(120) - 75 = 285ft

Therefore, the dimensions of the rectangular base of the building with the given perimeter are 120ft and 285ft.

Learn more about rectangles here: brainly.com/question/17043956

#SPJ1

You might be interested in

Evaluate the function for an input value of 3. f (x) = -4x^2 – 3x – 5

Lina20 [59]

Answer:

Step-by-step explanation:

<u>Function given:</u>

f(x) = -4x² – 3x – 5

Evaluate the function for an input value of 3

<u>Input value is x = 3, output value is:</u>

f(3) = -4(3²) – 3(3) – 5 = -4(9) - 9 - 5 = -36 - 14 = -50
f(3) = -50

3 0

3 years ago

An equation of the line of best fit for a data set is y=0.54x+3.04. Describe what happens to the line of best fit when each y-va

Ghella [55]

Answer:

The slope decreases and the y-intercept decreases.

Explanation:

Red is original, blue is when y is doubled.

5 0

3 years ago

Hiii... can someone help on this......????!

tekilochka [14]

I'll fv.*king kill your entire family you gay b17ch

7 0

3 years ago

Read 2 more answers

Which pair of triangles can be proven congruent by SAS?

ivolga24 [154]

Answer:

Second option

Step-by-step explanation:

They have two congruent pairs of sides and one congruent pair of angles.

4 0

2 years ago

Consider f and c below. f(x, y) = (3 + 4xy2)i + 4x2yj, c is the arc of the hyperbola y = 1/x from (1, 1) to 3, 1 3 (a) find a fu

irga5000 [103]

We want to find a scalar function $f(x,y)$ such that $\nabla f(x,y)=\mathbf f(x,y)=\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j$ .
So we need to have
$\dfrac{\partial f}{\partial x}=3+4xy^2$
Integrating both sides with respect to $x$ gives
$f(x,y)=3x+2x^2y^2+g(y)$
Differentiating with respect to $y$ gives
$\dfrac{\partial f}{\partial y}=4x^2y+\dfrac{\mathrm dg}{\mathrm dy}=4x^2y$ $\implies\dfrac{\mathrm dg}{\mathrm dy}=0$ $\implies g(y)=C$
So we find that
$f(x,y)=3x+2x^2y^2+C$
By the fundamental theorem of calculus, we then know the line integral depends only on the values of $f(x,y)$ at the endpoints of the path. Therefore

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(3,\frac13\right)-f(1,1)=11-5=6$

4 0

3 years ago