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2 years ago

A building in a city has a rectangular base. The length of the base measures 75 ft less than three times the width. The

Mathematics

1 answer:

MariettaO [177]2 years ago

7 0

The dimensions of the rectangular base of the building with the given perimeter are 120ft and 285ft.

<h3>What are the dimensions of the rectangle base?</h3>

The perimeter of rectangle is expressed as;

P = 2( l + w )

Given the data in the question;

Let x represent the width of the rectangular base.

Width w = x
Length = l = 3x-75
Perimeter P = 810ft

Plug these values into the equation above.

P = 2( l + w )

810 = 2( (3x-75) + x )

810 = 6x - 150 + 2x

810 = 8x - 150

8x = 810 + 150

8x = 960

x = 960/8

x = 120

Hence,

Width of the rectangle = x = 120ft

Length of the rectangle = 3x-75 = 3(120) - 75 = 285ft

Therefore, the dimensions of the rectangular base of the building with the given perimeter are 120ft and 285ft.

Learn more about rectangles here: brainly.com/question/17043956

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Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters

s344n2d4d5 [400]

The various answers to the question are:

To answer 90% of calls instantly, the organization needs four extension lines.
The average number of extension lines that will be busy is Four
For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

<h3>How many extension lines should be used if the company wants to handle 90% of the calls immediately?</h3>

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

$P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$$

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$$

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$$

Generally, the equation for is mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

The probability that a call will receive a busy signal if four extensions lines are used is,

$P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$$

Therefore, the average number of extension lines that will be busy is Four

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

$P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$$

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

Read more about signal

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3 0

2 years ago

Skill: Calculate the surface area of a pyramid

Aleks04 [339]

Answer:

44.84

Step-by-step explanation:

The formula for this is lw + l √(w/2)^2 + h^2 + w * √(l/2)^2 = h^2

After that, you just input the values to get a total of 44.84 inches

8 0

3 years ago

Read 2 more answers

Order the following fractions from least to greatest<br> 3/8 3/4 5/16 1/2

valentinak56 [21]

Answer:5/16 3/8 3/4 1/2

7 0

3 years ago

Read 2 more answers

-2/5x - 1/2 + x = -40/11

IgorLugansk [536]

Answer: x = 6.56

Step-by-step explanation: -0.4x - 0.5 + x = 3.63

-0.4x^2 - 0.5 = 3.63

-0.4x^2 = 4.13

0.63x = 4.13

x = 6.56

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2 years ago

Input, x 4 8 12 16 20 output y 21 37 53 69 85 what is the equation

BigorU [14]

Answer:

The equation is y = 4x + 5

Step-by-step explanation:

To find the equation to this table, pick two ordered pairs and use the slope formula to find the slope. For this we'll use (4, 21) and (8, 37).

m(slope) = (y2 - y1)/(x2 - x1)

m = (37 - 21)(8 - 4)

m = 16/4

m = 4

Now we can use that slope along with any point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 21 = 4(x - 4)

y - 21 = 4x - 16

y = 4x + 5

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4 years ago