(12,24)
Hope it helps love.
-Joker7721
Answer: Choice CThe non-pencil part of the compass is placed at point G. The compass must be kept the same width that was used to form the arc shown. The idea is to draw another arc so that it starts above G (so its on the opposite side of point A) and traces out a similar path as the arc in the diagram.
Check out the attached image to see what I mean. The new second arc is shown in red.
Answer:
Yes, △ABC ∼ △FED by AA postulate.
Step-by-step explanation:
Given:
Two triangles ABC and FED.
m∠A = m∠B
m∠C = m∠A + 30°
m∠E = m∠F = 
m∠D =
°.
Now, let m∠A = m∠B = 
So, m∠C = m∠A + 30° = 
Now, sum of all interior angles of a triangle is 180°. Therefore,
m∠A + m∠B + m∠C = 180

Therefore, m∠A = 50°, m∠B = 50° and m∠C = m∠A + 30° = 50 + 30 = 80°.
Now, consider triangle FED,
m∠D+ m∠E + m∠F = 180

Therefore, m∠F = 50°
m∠E = 50° and
m∠D = 
So, both the triangles have congruent corresponding angle measures.
m∠A = m∠F = 50°
m∠B = m∠E = 50°
m∠C = m∠D = 80°
Therefore, the two triangles are similar by AA postulate.
Answer:
The slope of the graph is 3/5
Step-by-step explanation:
We know that slope is nothing but rise over run. In this equation, the spacing is 3 points different vertically and 5 horizontally. If we do Rise Over Run, we will get 3/5 as our answer.
First check whether the point (-6,8) is the solution to any of the equations. To check, just plug in the x and y values of the points into the equation and see if they give you a true statement.
5(-6)+3(8)=-6
-30+24=-6
-6=-6
That's a true statement so the point is the solution to the first equation.
2(-6)+(8)=-4
-12+8=-4
-4=-4
It is a true statement so the point is a solution for both equations
There are no other solution because lines can only intersect in one or infinite points, but that is only if they are the same lines, which is not true in this circumstance.
A. It is the only solution to the set.
Hope this helps.