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2 years ago

Is it possible for a number to be a rational number that is not an interger but is a whole number. Explain

Mathematics

1 answer:

mylen [45]2 years ago

5 0

Whole numbers are a subset of integers, which in turn are a subset of rational numbers.

So, every whole number is an integer, and every integer is a rational number.

So, it is possible for a rational number not to be an integer. Think of any decimal number: 1.356 is a rational number, but it's not an integer.

On the other hand, if a number is not an integer, it can't be a whole number, because all whole numbers are integers.

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Distrubutive property (m-3)(-10)?

mrs_skeptik [129]

Answer: -10m + 30

Step-by-step explanation:

Given expression

(m - 3) (-10)

Expand parentheses and apply the distributive property

=m · (-10) - 3 · (-10)

Simplify by multiplication

= $\boxed{-10m+30}$

Hope this helps!! :)

Please let me know if you have any questions

4 0

3 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago

The measure of angle 1 is 39 degrees. What is the measure of the angle adjacent to angle 1?

Bogdan [553]

Answer:

Step-by-step explanation:

90-39 = 51

6 0

2 years ago

The equation of line A is y = 7x + 12. Line B is perpendicular to line A and passes through the point . What would be the soluti

max2010maxim [7]

Since B is perpendicular to A. We can say that the gradient of B will be -1/7 (product of the gradients of 2 perpendicular lines has to be -1).
Now we know that the equation for B is y=-(1/7)x + c with c being the y intercept.
Since the point isnt specified in the question, we could leave the equation like this.
But if there is a given point that B passes through, just plug in the x and y values into their respective places and solve to find c. That should give you the equation for b.
Now, to find the solution of x, we have 2 equations:
1) y=7x+12
2)y=-(1/7)x+c

In this simultaneous equation we see that y is equal to both the expressions. So,
7x+12=-(1/7)x+c

Now, since the value of c is not found, we cannot actually find the value of x, but if we would find c, we could also find x since it would only be a matter of rearranging the equation.
And there you go, that is your solution :)

3 0

2 years ago

NEED HELP ASAP!! Use the function below to find F(3)

kvv77 [185]

It’s gonna be 1/125.

Since it’s F(3), you need to plug the 3 into the x. Then expand it into 1/5 times 1/5 times 1/5, which gets you 1/125

5 0

2 years ago

Read 2 more answers