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2 years ago

Cynthia Besch wants to buy a rug for a room that is 21 ft wide and 27 ft long. She wants to leave a

Mathematics

1 answer:

fgiga [73]2 years ago

8 0

Answer:

Dimension of rug $\left ( 19.4935feet,19.4935 feet\right )$

Step-by-step explanation:

Given,

Area of room $=21\times 27$ $=567$ square feet

Area of carpet $=187$ square feet

Let dimension of rug be (a,a)feet

Area of rug $=567-187=380$ square feet

$a^{2} =380$

$a =\sqrt{380}=19.4935 feet$

Dimension of rug $\left ( 19.4935feet,19.4935feet \right )$

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A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

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2 years ago

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lys-0071 [83]

The answer would be C. 73.6. If you use the correct math without rounding it would be 73.5792. Hope this helps!

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3 years ago

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GenaCL600 [577]

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