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Oksi-84 [34.3K]
3 years ago
15

There was no more rainfall for the rest of the day. Click on the graph until the graph that best represents the given statement

appears.

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
4 0

Answer:

the the third graph

Step-by-step explanation:

this is because the third graph shows a correlation of the time and when the rainfall in a proporational relesho=inshop

Komok [63]3 years ago
3 0

Answer:

the third graph :)

Step-by-step explanation:

each hour the rain is increasing by 2 drops.

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Your salary in x years is modeled an the exponential growth

The equation that determines your salary in x years is y = 45000(1.05)^x

<h3>How to model the salary growth?</h3>

The model of the exponential growth is given as:

y = a(1 + r)^x

From the question, we have:

Initial salary, a = 45000

Raise, r = 5%

So, the equation becomes

y = 45000(1 + 5%)^x

Evaluate the sum

y = 45000(1.05)^x

Hence, the equation that determines your salary in x years is y = 45000(1.05)^x

Read more about exponential functions at:

brainly.com/question/11464095

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Perform the indicated operation
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A grass fertilizer is sold in 5-pound bags. Stuart calculates that he needs enough fertilizer to cover 4,350 square feet. If eac
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Step-by-step explanation:

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2 years ago
Change the subject of the formula L = v 4kt - p to k.
Romashka [77]

Answer:

\boxed{k = \frac{L^2 + p}{4t}}

General Formulas and Concepts:

<u>Algebra I</u>

Basic Equality Properties

  1. Multiplication Property of Equality
  2. Division Property of Equality
  3. Addition Property of Equality
  4. Subtraction Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle L = \sqrt{4kt - p}

<u>Step 2: Solve for </u><u><em>k</em></u>
We can use equality properties to help us rewrite the equation to get <em>k</em> as our subject:

Let's first <em>square both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}

Next, <em>add p to both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}

Next, <em>divide 4t by both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}

We can rewrite the new equation by swapping sides to obtain our final expression:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}

∴ we have <em>changed</em> the subject of the formula.

---

Learn more about Algebra I: brainly.com/question/27698547

---

Topic: Algebra I

6 0
1 year ago
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