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andreyandreev [35.5K]

3 years ago

7

A recipes calls for 1/4 cups of flour. Carter only has a measuring cup that holds 1/8 cup. how can carter measure the flour he n

eeds for his recipe?

2 answers:

maksim [4K]3 years ago

8 0

You would use the 1/8 cup twice to complete the recipe

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deff fn [24]3 years ago

4 0

Convert to like denominators. 1/4 is equal to 2/8, so he can take two cups of the measuring cup he’s using to get the amount of flour needed.

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vladimir1956 [14]

Step-by-step explanation:

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3 years ago

A fan is marked up 40% on the original price. The original price was $20. What is the new price of the fan before sales tax?

Andre45 [30]

Answer:

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Step-by-step explanation:

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3 years ago

What is the surface area of a rectangular prism?<br><br>length : 3<br>width : 3<br>height = 5

elixir [45]

Since it is a rectangular prism, the front and back are the same. the sides are the same and the top and bottom are the same. You would find the area of the front and back first. Since they both have the same measurements, you can find the area of one of the faces and multiply by 2.
A=BH
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A=15
15x2=30
So the front and back's area is 30. Now you find the area of both sides. They are both rectangle so the formula is A=BH.
A=BH
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4 0

3 years ago

Celeste rides her bike to work, averaging 12 miles per hour. On her way home she averages 8 miles per hour. If the total trip ta

elena-14-01-66 [18.8K]

20 miles from work is the total distance

5 0

2 years ago

What is wrong with the following equation?x2+xâˆ’20/xâˆ’4=x+5a. (xâˆ’4)(xâˆ’5)â‰ x2+xâˆ’20b. The left-hand side is not defined f

joja [24]

Answer:

The answer to this question can be defined as follows:

In part (i), the answer is "option d".

In part (ii), the answer is "option 2".

Step-by-step explanation:

Given:

Part (a)

$\Rightarrow \bold{\frac{x^2+x-20}{x-4}=x+5}\\\\$

Solve the above equation:

$\Rightarrow x^2+x-20=(x+5)(x-4)\\\\\Rightarrow x^2+x-20=(x^2-4x+5x-20)\\\\\Rightarrow x^2+x-20=x^2-4x+5x-20\\\\\Rightarrow \boxed{x^2+x-20=x^2+x-20}\\$

Given:

Part (b)

$\Rightarrow \bold{ \lim_{x \to \3} \frac{x^2+x-12}{x-3}= \lim_{x \to 3} (x+4)}\\\\$

Solve the above equation:

factor of $\Rightarrow x^2+x-20 =(x-3)(x+4)$

$\Rightarrow \lim_{x \to \3} \frac{(x-3)(x+4)}{x-3}= \lim_{x \to 3} (x+4)\\\\\Rightarrow \lim_{x \to \3} (x+4)= \lim_{x \to 3} (x+4)\\\\$

apply limit value:

$\Rightarrow (3+4)= (3+4)\\\\\Rightarrow 7= 7$

6 0

3 years ago