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sergejj [24]
3 years ago
5

How do i Simplify, using order of operations: the following problem?

Mathematics
1 answer:
spayn [35]3 years ago
7 0

Hello!

Explanation: This question's it's about the order of operations. It stands parenthesis, exponents, multiply, divide, add, and subtract. It can also go left too right.

First, you had to do is calculate parenthesis first.

3*2+(4+9/3)

9/3=3

4+3=7

3*2+7

Next, multiply from left too right.

3*2=6

6+7=13

Then you add left too right.

13+6

13+6=19

Final answer: → \boxed{=19}

Hope this helps!

Thank you!

Have a great day!

-Charlie

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Answer:

5/4324 = 0.001156337

Step-by-step explanation:

To better understand the hyper-geometric distribution consider the following example:

There are 100 senators in the US Congress, and suppose 60 of them are republicans  so 100 - 60 = 40 are democrats).

We extract a random sample of 30 senators and we want to answer this question:

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The answer using the h-g distribution is:

\large \frac{\binom{60}{10}\binom{100-60}{30-10}}{\binom{100}{30}}=\frac{\binom{60}{10}\binom{40}{20}}{\binom{100}{30}}

Now, imagine there are 56 senators (56 lottery numbers), 6 are republicans (6 winning numbers and 50 losers), we extract a sample of 6 senators (the bettor selects 6 numbers). What is the probability that 4 senators are republicans? (What is the probability that 4 numbers are winners?).

<em>As we see, the situation is exactly the same,</em> but changing the numbers. So the answer would be

\large \frac{\binom{6}{4}\binom{56-6}{6-4}}{\binom{56}{6}}=\frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}

Now compute each combination separately:

\large \binom{6}{4}=\frac{6!}{4!2!}=15\\\\\binom{50}{2}=\frac{50!}{2!48!}=1225\\\\\binom{50}{6}=\frac{50!}{6!44!}=15890700

and now replace the values:

\large \frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}=\frac{15*1225}{15890700}=\frac{18375}{15890700}=\frac{5}{4324}

and that is it.

If the decimal expression is preferred then divide the fractions to get 0.001156337

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Answer:

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