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nataly862011 [7]
3 years ago
7

In the lab, students decomposed a sample of calcium carbonate by heating it over a Bunsen burner and collected carbon dioxide ac

cording to the following equation: CaCO3(s) CaO(s) CO2(g) (a) How many mL of carbon dioxide gas were generated by the decomposition of 3.18 g of calcium carbonate at STP
Chemistry
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

712.32ml

Explanation:

From the equation, we can see that one mole of limestone yielded one mole carbon iv oxide.

Now, we need to know the actual number of moles reacted. The actual number of moles reacted = mass reacted ÷ molar mass of limestone.

The molar made of limestone is = 100g/mol.

Hence, the no of moles = 3.18÷100 = 0.0318 mole

Now, we need to know the number of moles of carbon iv oxide yielded. Using the 1 to 1 mole ratio, this shows that 1 0.0318 of Carbon iv oxide was yielded.

We know 1 mole of a gas at s.t.p occupies a volume of 22.4dm^3 , hence, 0.0318 will occupy; 0.0318b× 22.4 = 0.71232dm^3

1000ml = 1dm^3

Converting the volume to ml = 0.71232 × 1000 = 712.32ml

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Answer:

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The total energy or intrinsic energy of a system is called the enthalpy. In thermochemistry, we have two types of enthalpy changes which are:

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Entropy is the degree of randomness or disorderliness of a system. When a phase change occurs from liquid to solid, freezing takes place. Such a change increases the orderliness of a system and entropy diminishes. Here, entropy is negative.

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