Answer:
√(p²-4q)
Step-by-step explanation:
Using the Quadratic Formula, we can say that
x = ( -p ± √(p²-4(1)(q))) / 2(1) with the 1 representing the coefficient of x². Simplifying, we get
x = ( -p ± √(p²-4q)) / 2
The roots of the function are therefore at
x = ( -p + √(p²-4q)) / 2 and x = ( -p - √(p²-4q)) / 2. The difference of the roots is thus
( -p + √(p²-4q)) / 2 - ( ( -p - √(p²-4q)) / 2)
= 0 + 2 √(p²-4q)/2
= √(p²-4q)
Answer:
x+y = 112 ........ (1)
x-y = 62............ (2)
from (1) and (2)
2x = 174
x = 174/2
x = 87
sub x = 87 in (1)
x+y = 112
87+y = 112
y = 112 - 87
y = 25
so the numbers are 87 and 25
Step-by-step explanation:
Answer:
i thinks the answer is the fourth, which an= 3-2(n-1)
<h3>Answer:</h3>
x = 2
<h3>Explanation:</h3>
The rule for secants is that the product of segment lengths (on the same line) from the point of intersection to the points on the circle is a constant for any given point of intersection. Here, that means ...
... 3×(3+5) = 4×(4+x)
... 6 = 4+x . . . . divide by 4
... 2 = x . . . . . . subtract 4
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<em>Comment on this secant relationship</em>
Expressed in this way, the relationship is true whether the point of intersection is inside the circle or outside.
