Answer: x = 3, y = 1 OR (3, 1)
Step-by-step explanation:
let 2x + 3y = 9 be [a] & y = x − 2 be [b]
First, lets substitute [b] into [a] and solve for x
2x + 3( x - 2) = 9
2x + 3x = 9 + 6
5x = 15
x = 3
Now, since x = 3, we can substitute for x in [b]
⇒ y = 3 - 2
y = 1
∴ the solution for the system of equations is x = 3, y = 1 OR (3, 1)