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Yuliya22 [10]
3 years ago
15

What percentage of the data values represented on a box plot falls between the minimum value and the lower quartile?

Mathematics
2 answers:
AlladinOne [14]3 years ago
8 0

Answer:

A. 25%

Step-by-step explanation:

Because it asks you where one section to another section (on a box plot there are four areas containing 25% within each one.)

Butoxors [25]3 years ago
4 0

Answer:

first 25%

Step-by-step explanation:

A quartile is a quarter, so the first 25% falls between the minimum and lower quartile

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A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
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Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

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Step-by-step explanation:

Ken class has a median of 84 while Judy class a median of 87

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