The solution for the questions is mathematically given as
a)
t-distribution.
b)
the confidence interval for the mean, based on 98 percent of the sample, is ( 6.3952, 7.3048 )
c) the value of the is within the range of the 98 percent confidence interval for the mean, which is between 6.3952 and 7.3048, then accept H_0; otherwise, reject H _0.
d)
you should conduct a poll with around 123 students to determine the average amount of time that students spend sleeping at your institution.
<h3>What is the distribution to use?</h3>Generally, the equation for is mathematically given as
a.
In this case, the standard deviation of the population is unknown.
As a result, we make use of the t-distribution.
b)
We wish to generate a confidence interval with a 98 percent likelihood for the mean.
Because of this,
(6.3952,7.3048)
Therefore, the confidence interval for the mean, based on 98 percent of the sample, is ( 6.3952 , 7.3048 )
c )
If the value of the mu _0 is within the range of the 98 percent confidence interval for the mean, which is between 6.3952 and 7.3048, then accept H_o; otherwise, reject H_0.
d . Here, we want to determine the sample size
Therefore,
n=122.4364
In conclusion, you should conduct a poll with around 123 students to determine the average amount of time that students spend sleeping at your institution.
Read more about probability
#SPJ1