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sergiy2304 [10]
3 years ago
8

Card 5 of 9

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

<5 of

>9 of

<4of

jadi =18 of

Step-by-step explanation:

sorry ya kalo jawaban nya salah

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u<2 so

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3 years ago
Motorola used the normal distribution to determine the probability of defects and the number
vovangra [49]

Answer:

a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4

b.p=0.0026,total defects=2.6

c.Less of the items produced will be classified as defects.

Step-by-step explanation:

a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.

\mu=10,\sigma=0.15\\Therefore:-\\z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.15}\approx-1.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.15}\approx+1.0\\P(x10.15)=P(Z+1.0)\\=2P(Z

Total defects=Production*Probability

                      =0.3174*1000

                       =317.4

b. \mu=10,\sigma=0.05

therefore:-

z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.05}\approx-3.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.05}\approx+3.0\\\\=P(x10.15)=P(Z+3.0)\\=2P(Z

Defects=Probability*Production

            =0.0026*1000

             =2.6

c.Reducing process variation results in a significant reduction in the number of unit defects.

3 0
3 years ago
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