Given:
The height of a golf ball is represented by the equation:
To find:
The maximum height of of Anna's golf ball.
Solution:
We have,
Differentiate with respect to x.
For critical values, 
.
Differentiate y' with respect to x.
Since double derivative is negative, the function is maximum at .
Substitute in the given equation to get the maximum height.
Therefore, the maximum height of of Anna's golf ball is 6.25 units.
30 + 5h = 20h
30 = 20h - 5h
30 = 15h
30/15 = h
2 = h
at 2 hrs, they both charge the same rate...
30 + 5(2) = 30 + 10 = 40
20h = 20(2) = 40
so at 2 hrs, they both charge $ 40
12 + 26 + 125 = 163
163 + 0.056(163) = 163 + 9.13 = 172.13
Try substituting some values in, and you will get your answer.
I'll do the first two.
y = (0) + 4 [=4]
y = (2) + 4 [=6]
In the table, the first two values for y are 6 and 8.
The first two values for y = x + 4 are 4 and 6.
Therefore, we can assume that the rate of change in the function y = x + 4 is less than the rate of change of the function represented in the table.
PART A
s = <span>the number of packets of strawberry wafers ;
c = </span><span>the number of packets of chocolate wafers ;
3 </span>× s + 1 × <span>c = 30 ;
s + c = 22 ;
PART B
</span>The method of solving "by substitution"<span> works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.
</span>
c = 30 - 3s;
s + ( 30 - 3s ) = 22;
30 - 2s = 22;
30 - 22 = 2s;
8 = 2s;
s = 4 ;
c = 30 - 12 ;
c = 18 ;
