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Hunter-Best [27]
4 years ago
13

Find the magnitude v and direction angle θ, to the nearest tenth of a degree, for the given vector v. v = -4i - 3j

Mathematics
1 answer:
klemol [59]4 years ago
7 0
The answer would be C
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What is the radius of a sphere that has a surface area of 951.1 in2?
dusya [7]

Answer:

FORMULA FOR SURFACE AREA OF SPHERE = 4 pi r^2  

r = 6 " area = 4 pi X 6 X 6 = 144 pi " squared  

r = 12 "  

area = 4 X pi X 12 X 12 = 576 pi" squared  

ANSWER Area will be 4 times the original

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is 0.26 repeating (.26 reappearing) as a fraction in simplest form?
IRISSAK [1]
 <span>Is it 0.262626...? 
repeating decimals you have to write at least two of the repeats so it is obvious what is repeating. 

1000x = 262.62626... 
10x = 2.62626... 
1000x - 10x = 260 
990x = 260 
x = 26/99</span>
6 0
4 years ago
Add the two expressions.<br> 2x + 6 and 6.2 - 1<br> Enter your answer in the box.
madam [21]

Answer:

8x + 5

Step-by-step explanation:

By adding

2x + 6 + 6x -1

8x + 5

8 0
3 years ago
Can someone help me with problem please? It’s special right triangle: decimal answers (Round to the nearest tenth)
DochEvi [55]

Answer:

h= 4.6, c=7.1

Step-by-step explanation:

First you need to know in a 30 60 90 triangle the sides ratios are x, 2x and x√3, and for 45 90 45 it is x, x and x√2

so <em>h</em> is 8/√3 and you rationalize the bottom so it becomes 8√3/3. when you solve this and round to nearest hundred it becomes 4.6. for the second one, it is 5√2 and when you solve this and round, it becomes 7.1

8 0
3 years ago
Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ &lt; 55 A sample of 36 is used. Identify the p-value and state your con
Ket [755]

Answer:

Step-by-step explanation:

Given that:

H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }

Z = \dfrac{-1}{\dfrac{5.3}{6} }

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

b

For x = 53 and s = 4.6

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }

Z = \dfrac{-2}{\dfrac{4.6}{6} }

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

Conclusion: \  There  \ is \  sufficient \  evidence  \  to \  conclude \  that \mu < 55

c)

For x = 56 and s = 5.0

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

6 0
3 years ago
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