The circumcenter is found by finding the intersection of at least 2 perpendicular bisector segments.
Find the perpendicular bisector to segment AB. This is the line y = -3.5; the idea is that you find the equation of the horizontal line through the midpoint of AB. The midpoint has a y coordinate of -3.5. This line is shown in red horizontal line in the attached image below.
The midpoint of AC is 2.5, so the perpendicular bisector to AC is x = 2.5 which is shown as the vertical green line in the same diagram.
The red and green lines cross at the location (2.5, -3.5) which is the circumcenter's location. If you were to draw a circle through all three points A, B, & C, then this circle would be centered at (2.5, -3.5)
If point D is the circumcenter, then we know this
AD = BD = CD
basically the distance from the center to any point on the triangle is the same. This is due to the fact that all radii of the same circle are the same length.
<h3>Answer: (2.5, -3.5)</h3>
note: 2.5 in fraction form is 5/2 while -3.5 in fraction form is -7/2
Answer:
its finally sorry it tooke so long
Step-by-step explanation:
X over 2 = -7 comes out to
x
---- = -7. Mult. both sides by 2 to eliminate the fraction:
2
x = 2(-7) = - 14 (answer)
Answer:
The formula to find the voltage is:
![v=\sqrt{P*R}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7BP%2AR%7D)
And the voltage is 4 volts
Step-by-step explanation:
To get the equation of voltage you need to isolate v in one side of the equation. In order to do that, you need to remove the divisor/denominator and its square. How will you do that?
First, multiply both sides with R:
![P*R=\frac{v^{2} }{R} *R](https://tex.z-dn.net/?f=P%2AR%3D%5Cfrac%7Bv%5E%7B2%7D%20%7D%7BR%7D%20%2AR)
That would result into removing the divisor R from the right side of the equation:
![P*R=v^{2}](https://tex.z-dn.net/?f=P%2AR%3Dv%5E%7B2%7D)
Next, square-root both sides:
![\sqrt{P*R} =\sqrt{v^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7BP%2AR%7D%20%3D%5Csqrt%7Bv%5E%7B2%7D%20%7D)
That would result in removing the square of v from the right side of the equation:
![\sqrt{P*R} =v](https://tex.z-dn.net/?f=%5Csqrt%7BP%2AR%7D%20%3Dv)
Thus we get the equation,
.
To find out the voltage, simply replace R with 32 and P with 0.5
![v=\sqrt{0.5*32}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B0.5%2A32%7D)
![r=\sqrt{16}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B16%7D)
![r=4](https://tex.z-dn.net/?f=r%3D4)
Thus, the voltage is 4 volts.