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dybincka [34]
3 years ago
12

Which correctly describes the roots of the following cubic equation x^3-5x^2+3x+9=0?

Mathematics
1 answer:
Bad White [126]3 years ago
8 0

Answer:

C) Three real roots, two of which are equal in value is the right answer I believe.

Step-by-step explanation:


You might be interested in
What’s x in the question
Lina20 [59]

Answer:

x = 5/(a+3-b)

Step-by-step explanation:

ax+3x = bx+5

ax+3x-bx = 5

Take x as a common.

x(a +3 - b) = 5

x = 5/(a+3-b)

4 0
3 years ago
HELP ME PLS!!!! asap!!!!
Andrews [41]

Answer: Calvin has 13 quarters.


Step-by-step explanation:

Let Calvin have  x quarters.  

therefore amount of Calvin =  0.25 x    [ 1 quarter =  $0.25 ]

Number of dimes for Sara = x  

      [ Given that number of dimes of Sara = number of  quarters of Calvin

Amount of dimes for Sasha = 0.1x  [ 1 dime = $0.1 ]

Amount of Sasha without dime =  $1.95  [ given]

total amount of Sasha = 1.95 =+ 0.1x

Since amount of Calvin and Sasha is same  therefore

        0.25x  = 1.95 +0.1x

      0.25x -0.1x = 1.95

       0.15x = 1.95

           x = \frac{1.95}{0.15}

           x = 13

5 0
3 years ago
1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
scZoUnD [109]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<em>A) If the length of a rectangle was tripled, but the  width did not change?</em>

<em>Perimeter</em>

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

<u>Area</u>

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em>

<u>Perimeter</u>

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

<u><em>Area</em></u>

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

4 0
3 years ago
Find the solution of this system of equations -x-4y=-37 -2x-5y=-53
zzz [600]

Answer:

The solution in point form is (9,7) and the equation would be x+9, y=7

Step-by-step explanation:

By using moving the -4y to the right side and by flipping the signs you can turn the equation -x-4y=-37 into x=37-4y.

With this new equation you can use the substitution method and replace the x in -2x-5y=-53 with 37-4y, making it look like this: -2(37-4y)-5y=-53.

Then you solve for y getting y=7.

With the value of y, you can plug that into the equation x=37-4y so it will look like x=37-4(7)

Then you solve for x getting x=9

And with that you get the point (9,7)

7 0
3 years ago
Is there a proportional relationship between x and y?
Mumz [18]

Answer:

Unnnnnnnnnnnnnnnnnnnnnnnnbnbnnnn

5 0
3 years ago
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