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Rufina [12.5K]
3 years ago
9

Use the Pythagorean Theorem to find the exact value of x for the right triangle below. The picture below is not drawn to scale

Mathematics
2 answers:
baherus [9]3 years ago
6 0
\sqrt{x} 10
irakobra [83]3 years ago
4 0
According to pythagorean theorem
(sqrt20)² = (sqrt10)² + x², so x = sqrt(20-10) = sqrt 10
the answer is <span>x =  sqrt 10</span>
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(2x2 - 3x + 7) - (-3x2 + 4x - 7) <br>what is the combine terms​
Ugo [173]

Answer:

-7x+24

Step-by-step explanation:

(2*2-3x+7) - (-3*2+4x-7)

11-3x+13-4x

-7x+24

4 0
3 years ago
Read 2 more answers
The radius of the fruit is 3 times the radius of the seed. It is known that the seed has a volume of 100 cubic centimeters. What
kolezko [41]
The edible fruit=fruit-seed

alright

vsphere=4/3pir^3

so if the volume is 100
of the seed
100=\frac{4}{3}\pi r^3
find r
times both sides by 3/4
75=\pi r^3
divide both sides by pi
\frac{75}{\pi}= r^3
cube root both sides
\sqrt[3]{\frac{75}{\pi}}= r
this is the seed radius
3 times of taht is the radius of the fruit
3\sqrt[3]{\frac{75}{\pi}}=radiusfruit

input into equation
use radius fruit for r
V=\frac{4}{3}\pi r^3
V=\frac{4}{3}\pi (3\sqrt[3]{\frac{75}{\pi}})^3
V=\frac{4}{3}\pi (27)(\frac{75}{\pi})
V=\frac{8100\pi}{3\pi}
V=2700 cm^3

so the edible part is 2700-100=2600 cm³
6 0
3 years ago
Read 2 more answers
He number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the
denis-greek [22]

The function that represents the number of E.coli bacteria cells per 100 mL of water as t years elapses, and is missing in the question, is:

A(t)=136(1.123)^{4t}

Answer:

   Option A. 59%

Explanation:

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function::

  • A(t)=136(1.123)^{4t}

  • rate=(1.123)^{4t}=(1.123)^4=1.590

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

You can calculate it also using two consecutive values for t. For instance, use t =1 and t = 1

t=1\\\\ A(1)=136(1.123)^4\\\\\\t=2\\ \\ \\A(2)=136(1.123)^8\\ \\ \\A(2)/A(1)=1.123^8/1.1123^4=1.123^4=1.590

6 0
3 years ago
Hat is the 68th term of sequence -8.6,-7.2,-5.8,-4.4,
Umnica [9.8K]
First find the law
8.6-1.4n
so, 64th is 8.6-1.4x64
I think is -81
5 0
3 years ago
Find the limit !!!!!!
Tasya [4]

Answer:

1/8.

Step-by-step explanation:

Use l'Hopitals rule - we find the derivative of top and bottom of the fraction.

Derivative of the numerator = 0 - 1/2 (16 - x)^-1/2  -1

=  1 / [ 2 * (16 - x)^1/2

Derivative of the denominator =  1

When x approaches 0 this is 1 / (2*4)

= 1/8.

Another way to do this is to multiply top and bottom by  4 + (16 - x)^1/2

This  becomes   16 - (16 - x) / x(4 + (16-x)^1/2)

= 1 / (4 + (16 + x)^1/2

When x ---> 0

this = 1 /(4 + 4)

= 1/8.

6 0
3 years ago
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