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3 years ago

Name all of the radii of the circle.

1 answer:

34kurt3 years ago

4 0

The radius of a circle connects the center of the circle to a point on the circumference. Therefore, the radii are:
AB, AC, AD

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Anyone here wanna talk about random stuff?

amid [387]

Answer:

sure, ill start

Step-by-step explanation:

She danced like a swan, tall and graceful. Soak the cloth and drown the sharp odor.

5 0

3 years ago

3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?

Scorpion4ik [409]

Answer:

For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

If $\bigtriangleup = 0$ , the equation has only one solution.

In this problem, we have that:

$3x^{2} + kx + 3 = 0$

$a = 3, b = k, c = 3$

$\bigtriangleup = b^{2} - 4ac$

$\bigtriangleup = k^{2} - 4*3*3$

$\bigtriangleup = k^{2} - 36$

We will only have one solution if $\bigtriangleup = 0$ . So

$\bigtriangleup = 0$

$k^{2} - 36 = 0$

$k^{2} = 36$

$k = \pm \sqrt{36}$

$k = \pm 6$

For k = 6 or k = -6, the equation will have exactly one solution.

3 0

3 years ago

What is the prime factorization of 7?

ehidna [41]

Answer:

Seven is a prime number and therefore has No Prime factorization :)

8 0

3 years ago

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Translate the sentece into a equation

maw [93]

The answer would be 5x^3-2x^2=18

5 0

3 years ago

Read 2 more answers

What is the volume & surface?

iogann1982 [59]

Answer:

180

Step-by-step explanation:

I multiplied both sides

8 0

3 years ago