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SCORPION-xisa [38]
3 years ago
5

Name all of the radii of the circle.

Mathematics
1 answer:
34kurt3 years ago
4 0
The radius of a circle connects the center of the circle to a point on the circumference. Therefore, the radii are:
AB, AC, AD
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3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?
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Answer:

For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

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In this problem, we have that:

3x^{2} + kx + 3 = 0

So

a = 3, b = k, c = 3

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\bigtriangleup = k^{2} - 4*3*3

\bigtriangleup = k^{2} - 36

We will only have one solution if \bigtriangleup = 0. So

\bigtriangleup = 0

k^{2} - 36 = 0

k^{2} = 36

k = \pm \sqrt{36}

k = \pm 6

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