(2X-3)(4-3X)
=8X-6X²-12+9X
=-6X²+17X-12
That's your answer.
The inscribed circle has its center at the point of intersection of the angle bisectors, which also happen to be the medians. Hence the altitude of the triangle is 3 times the radius, or 12 inches.
The side length of this triangle is 2/√3 times the altitude, so the area is
... Area = (1/2)·b·h = (1/2)·(24/√3 in)·(12 in)
... Area = 48√3 in² ≈ 83.1384 in²
Hi, Cupcakesorinkles14 here to your aid your correct answer is
48x6 + 8x3.
Answer:
3x + y = -16
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given a system of equations are
5x+6y =-5
- 2x - 5y = -11
multiply '1' and Adding two system of equtions
+ 1 (5x + 6y = -5)
+ 1 (<u> -2x - 5y = -11)</u>
<u> 3x + y = -16 </u>
<u>Final answer:-</u>
5x + 6y = -5
<u> -2x - 5y = -11</u>
<u> 3x + y = -16 </u>
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Answer:
you would - 1 to -7 and get -8 then divide -8 by -2 than it would be 4
Step-by-step explanation: