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Misha Larkins [42]
3 years ago
8

Factor:(m+2)^2−(m+2)+mn·(n+2)+2n(n+2)

Mathematics
1 answer:
bazaltina [42]3 years ago
5 0
ANSWER
{(m + 2)}( {n}^{2} + 2n + m + 1)

EXPLANATION

The given expression is

{(m + 2)}^{2} - (m + 2) + mn(n + 2) + 2n(n + 2)

We factor to get,

= {(m + 2)}(m + 2 - 1) +n (n + 2) (m+ 2)

This implies that,

= {(m + 2)}(m + 1) +n (n + 2) (m+ 2)

We factor further to obtain,

= {(m + 2)}((m + 1) +n (n + 2))

or

= {(m + 2)}( {n}^{2} + 2n + m + 1)
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At Becky's Restaurant, 10 out of 25 customers order wheat rolls. The rest of the customers order cornbread. Which does NOT repre
LekaFEV [45]

Answer:

C. 25 ÷ 10

Step-by-step explanation:

A. 10/25

B. 2/5

C. 25 ÷ 10

D. 0.4

Total customers at Becky's restaurant = 25

Customers who order wheat rolls = 10

It means 10 out of 25 customers order wheat rolls

That is

10 / 25

Dividing both numerator and denominator by 5

= 2 / 5

2/5 in decimal

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The option Which does NOT represent the part of the customers who order wheat rolls

is 25/10

Option C. 25 ÷ 10

8 0
3 years ago
Consider the equation
muminat

Answer:

A. a=10\\ \\b\neq -8

B. a=10\\ \\b= -8

Step-by-step explanation:

Consider the equation

2(5x-4) = ax + b

A. This equation has no solutions when the coefficients at x are the same and the free coefficients are not the same.

First, use distributive property:

2(5x-4)=2\cdot 5x-2\cdot 4=10x-8

So, the equation is

10x-8=ax+b

This equation has no solutions when

a=10\\ \\b\neq -8

B. The equation has infinitely many solutions when the coefficients at x are the same and the free coefficients are the same too.

So, the equation

10x-8=ax+b

has infinitely many solutions when

a=10\\ \\b= -8

In other cases, the equation has a unique solution

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3 years ago
Expression tha have the same vaule
Vedmedyk [2.9K]
I don't know if this is the answer that you are looking for, but would the answer be all solutions?
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Plz answer and thank you
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A . It has a value GREATER than 8
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