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4 years ago

Need help!! ASAP!! Geometry

Mathematics

1 answer:

kodGreya [7K]4 years ago

7 0

Total 52 students.

52 - 17 = 35 students left
35 - 5 = 30 students left
30 - 2 = 28 students left

Each class has 11 students that play ONE sport, which means 22 total in 2 classes. You're on your own now! It's not that hard, I'm sure you'll figure it out.

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What is the conjugate of (x2-6)?

Mama L [17]

Answer:

2(x - 3)

Step-by-step explanation:

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3 years ago

The student council needs posters for the winter carnival the print shop charges $15 for each print job each poser will cost an

kirill115 [55]

Answer:

Step-by-step explanation:

C = 1.35n + 15

6 0

3 years ago

7 times as much as sum of 1/3 and 4/5

Salsk061 [2.6K]

So the formula is
7*(1/3+1/5) = x

First find the common denominator of the fractions. In this case the common denominator of 3 and 5 is 15 so we must convert them to 15ths. To do that we divide 15 by the denominator and take that answer and multiply the numerator by it.

So for 1/3 we take 15/3(denominator) = 5 and multiply the numerator (1) by it

5 * 1 = 5 so 1/3 converts to 5/15

Do the same for 1/5 we take 15/5 = 3 and multiply the numerator (4) by it

3*4 = 12 so 4/5 converts to 12/15

Now we add 5/15 and 12/15 = 17/15 so we have our formula now to

7*17/15

We make seven a fraction 7/1 and multiply across 7*17 = 119 and 15 * 1 = 15

We have 119/15 which when we divide and get 7 14/15 as your answer

8 0

3 years ago

Read 2 more answers

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Helga [31]

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3 0

3 years ago

There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is

shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, $n(P) = 6$

Number of orange socks, $n(O) = 4$

Two socks are picked without replacement.

Now, total number of socks, $n(T)=N(P)+n(O)=6+4=10$

Probability of picking the first cap as purple cap is given as:

$P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}$

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

$P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}$

Now, probability that both the picked caps are purple is given by their probability product. This gives,

$P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33$

Therefore, the probability that he picked 2 purpled socks is 0.33

4 0

3 years ago