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patriot [66]
3 years ago
10

Helpp Based on the histogram above, which of the following statements must be true

Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0

Answer:

b

Step-by-step explanation:

because the price of money is maximum 2,500

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The sum of the areas of two circles is 80 pie square meters. Find the length of a radius of each circle if one of them is twice
Svetach [21]

Answer:

The radius of the circles are 4\ m  and   8\ m

Step-by-step explanation:

Let

x-----> the radius of larger circle

y----> the radius of smaller circle

we know that

\pi x^{2} +\pi y^{2}=80\pi

x^{2} +y^{2}=80 -----> equation A

Remember that

x=2y -----> equation B

substitute equation B in equation A and solve for y

(2y)^{2} +y^{2}=80

4y^{2} +y^{2}=80

5y^{2}=80

y^{2}=16

y=4\ m

Find the value of x

x=2y

x=2(4)=8\ m

therefore

The radius of the circles are 4\ m  and   8\ m

4 0
3 years ago
Help ! I AM Not sure what to do
o-na [289]
The answer is (3,5)
5 0
2 years ago
What is the measure of Y? 4·9=36=36/4
alexira [117]

Answer:

Figure or Diagram Mandatory

GOOD LUCK FOR THE FUTURE! :)

3 0
3 years ago
I’ll mark brainlest:( i need help!
enyata [817]

Answer: Choice A)  3 \sqrt{26}

==================================================

Work Shown:

\text{The two points are } (x_1,y_1) = (6,7) \text{ and }  (x_2,y_2) = (3,-8)\\\\d = \text{Distance between } (x_1,y_1) \text{ and } (x_2,y_2)\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} = \text{Distance Formula}\\\\d = \sqrt{(6-3)^2+(7-(-8))^2}\\\\d = \sqrt{(6-3)^2+(7+8)^2}\\\\

d = \sqrt{(3)^2+(15)^2}\\\\d = \sqrt{9+225}\\\\d = \sqrt{234}\\\\d = \sqrt{9*26}\\\\d = \sqrt{9}*\sqrt{26}\\\\d = 3\sqrt{26}\\\\

When going from 234 to 9*26, the idea here is to factor where one factor is the largest perfect square possible. That way we can use the rule \sqrt{x*y} = \sqrt{x}*\sqrt{y} to break up the root and simplify.

7 0
4 years ago
why was the value of y for the function y =5x + 1 always be greater than that for the function y=4x+2 when x>1
Galina-37 [17]
Lets compare both equations so we can explain the reason for it, and see it clearly:
<span>y1 = 5x + 1 
</span><span>y2 = 4x + 2
y1 > y2
</span>5x + 1 > 4x + <span>2
</span>To see why that happens we need to solve for x:
5x - 4x > 2 - 1
x > 1
Therefore, the first equation is greater than the second for values of x > 1
6 0
3 years ago
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