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Lana71 [14]
3 years ago
7

I need to 2,4,6,8 But please send me the work too

Mathematics
1 answer:
Ugo [173]3 years ago
4 0

ok for number 2.)   2+8+1+5+1+3+1+7+5+4+3+1=41 and 41 divided by the number of number which is 12= 3.41666666667

the mean for number 2 is 3.41666666667.

for the median you put the number from least to greatest, like so:

1, 1, 1, 1, 2, 3, 3, 4, 5, 5, 7, 8.

The middle is 3 and 3 so 3+3 divided by 2 is 6 so the median is 6.

I cant do mode but range is 8-1 divided by 2

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a

Step-by-step explanation:

because it's is very important

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3 years ago
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Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10
Vladimir [108]

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000  (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

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3 years ago
There was a bowl with 120 candies in it. Billy, Bob and Buck found the bowl. Billy ate 2/12 of the candies, Bob ate 3/12 and Buc
blagie [28]

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20 candies left.

Step-by-step explanation:

5 0
3 years ago
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3 years ago
7. Solve for 6s3(5s2)(3s4) =
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Simplify  (we cannot solve if there is no equals)

6s^3(5s^2)(3s^4)

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90 s^(9)

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