Answer:
78 and 46
Step-by-step explanation:
Answer:
The proportion of the offspring from the cross PpRr × PpRr that are expected to have white flowers and wrinkled seeds is 1/16 or 6.25%.
Step-by-step explanation:
The uppercase letter represents the dominant allele, while the lowercase represents the recessive allele. The dominant allele determines the phenotype (observable trait) when it is present.
When you cross heterozygous individuals for each trait, each individual of the offspring has the probability of 1/6 of each combination of four alleles (two for each trait). Because the dominant allele determines the phenotype when it is present, the probability of dominant phenotypes is higher than recessive phenotypes.
Proportions of each phenotype in the offspring from the cross PpRr × PpRr are:
Purple flowers with round seeds: 9/16
Purple flowers with wrinkled seeds: 3/16
White flowers with round seeds: 3/16
White flowers with wrinkled seeds: 1/16
The proportion of individuals with white flowers and wrinkled seeds is the lowest because they are homozygous recessive for both traits.
Answer:
Step-by-step explanation:
Given claim : From the time shoots are planted 90 days on average are required to obtain the first berry.
. The sample mean is 92.3 days. The corporation wants to know if the mean number of days is different from the 90 days claimed.
As we know that the null hypotheses shows there is no statistical difference between the groups but the alternative hypothesis is opposite to it, it shows there is difference.
Thus , the correct hypotheses will be :-
Answer:
Step-by-step explanation:
Calculation
Divide your interest rate by the number of payments you'll make that year. ...
Multiply that number by your remaining loan balance to find out how much you'll pay in interest that month. ...
Subtract that interest from your fixed monthly payment to see how much in principal you will pay in the first month.
Answer:
B has a smaller initial population of 500
Step-by-step explanation:
Given
See attachment for complete question
Required
The bacteria with the smaller initial population
The initial population is at x = 0
For bacteria A;
when 
For bacteria B, we have:
Substitute 0 for x
So; when x = 0
and
Because; 500 < 600
We can conclude that B has a smaller initial population of 500
