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harina [27]
3 years ago
5

3. What three numbers are the Pythagorean triple generated by using 4 for x and 1 for y. Remember to use the formulas:

Mathematics
1 answer:
Gnom [1K]3 years ago
5 0

Given:

The three equations for the three numbers are

a=x^2-y^2

b=2xy

c=x^2+y^2

To find:

The Pythagorean triple generated by using 4 for x and 1 for y.

Solution:

Substituting x=4 and and y=1 in the given equations, we get

a=4^2-1^2

a=16-1

a=15

In the same way find b and c.

b=2(4)(1)

b=8

The third number is

c=4^2+1^2

c=16+1

c=17

The required Pythagorean triple is 8, 15, and 17.

Therefore, the correct option is C.

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D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



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3 years ago
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Answer:

Solution given;

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radius [r]=8cm

we have

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=270°/360°×2×3.14*8=37.68cm

<u>length of the </u><u>arc</u><u> </u><u>is</u><u> </u><u>37.68</u><u>cm</u><u>.</u>

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To find this just divide 15 by 1250 and get <span>0.012
to find the percent just multiply </span><span>0.012 by 100 : 1.2%
the answer is 1.2%</span>
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