Answer:
Option C: y=-1/2x + 8
Step-by-step explanation:
So we have the options:
A) y=2x+5
B) y=-1/2x+4
C)y=-1/2x+8
D)y=-2x+5
But first let's define what parallel even is. When two lines are parallel it means that there slope is the same value and the same sign, while there y-intercepts are different, because if they were the same, then they wouldn't be parallel, they would just be the same exact line.
So we're given the equation in standard form. To find the slope we can change it so it's in the form of y=mx+b. This can be done by simply isolating y. The reason we want it in the slope-intercept form is because m represents the slope and b represents the y-intercept. m is the slope because as x increases by 1 the y-value will increase by m. So the "rise" will be m and the "run" will be 1, thus the slope will be m/1 or in other words m because the slope is defined as rise/run. So let's start the steps to isolating y
Original equation
2x+4y=16
Subtract 2x from both sides
4y=-2x+16
Divide both sides by 4
y = -1/2x + 4
Here we have it in slope-intercept form. In this case the slope, or m, is -1/2 and the y-intercept or b is 4. So now let's look at the other equations.
Option A: This equation has a slope of 2, which is not the same as -1/2 so it is not parallel
Option B: This equation has a slope of -1/2 which is the same as -1/2 so it might be parallel. But look at the y-intercept it's 4, that's the same y-intercept as the original equation. This means the two equations are equal and not parallel
Option C: This equation has a slope of -1/2 which is the same as -1/2 so it might be parallel. It has a y-intercept of 8 which is not the same as 4, so the two lines are parallel and not equal! This is the answer
Answer:
= 0.0596516 mi/h
Step-by-step explanation:
Just do 4 minutes divided by 6.4 meters
This question is very oddly worded. The domain is the set of x-values, but this is a set of (x,y) ordered pairs.
I'm reading this question as "Here's a function, { (1,5), (2,1), (-1,-7) }. If this is reflected over the x-axis, what's the range?"
Assuming that is the question that is meant to be asked, reflecting a function over the x-axis will just change the signs of the y-values.
(1,5) -> (1,–5)
(2,1) -> (2,–1)
(-1,-7) -> (-1,+7)
I'd pick the third option.
