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exis [7]
3 years ago
9

De NAGINIS UN

Mathematics
1 answer:
rewona [7]3 years ago
6 0
Find it out or loose it man
You might be interested in
Any 3 digit describe how to find the number that is 10 more
zavuch27 [327]
The answer would be 30
4 0
3 years ago
Read 2 more answers
Use a formula to find the monthly payment on a home mortgage of $84,400 at 4.884% interest for 15 years.
leonid [27]
The applicable formula is
  A = P(r/12)/(1 -(1+r/12)^(-12n))
where P is the principal amount,
r is the annual interest rate (compounded monthly), and
n is the number of years.

Using the formula, we find
  A = 84,400*(0.04884/12)/(1 -(1+0.04884/12)^(-12*15))
  = 84,400*0.00407/(1 -1.00407^-180)
  = 343.508/0.518627
  ≈ 662.34

The monthly payment on a mortgage of $84,400 for 15 years at 4.884% will be
  $662.34
6 0
3 years ago
How do i write the difference of a number x and 2 is 7 as an equation
HACTEHA [7]

You can quiet literally write the question as it is.

The difference of a number x and 2 is 7.

The difference of a number x and 2 can be written as x-2

is can be written as equal or =

This statement can be translated as x-2=7.

It is as simple as that!

5 0
3 years ago
Find an ordered pair to represent a in the equation<br> a=2b+c if b=(6,3) and c=(-4,8)
zaharov [31]

Answer:

The ordered pair to represent a in the equation a=2b+c if b=(6,3) and c=(-4,8) is: a=(8,14)

Step-by-step explanation:

b=(6,3)

c=(-4,8)

a=2b+c

Replacing b and c in the equation above:

a=2(6,3)+(-4,8)

Multiplying:

a=(2*6,2*3)+(-4,8)

a=(12,6)+(-4,8)

Adding:

a=(12+(-4),6+8)

a=(12-4,14)

a=(8,14)

8 0
3 years ago
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
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