A(w)=50w-w2 if the perimeter is 100, I plugged in possible values for the width...I used w=15 and length = 35 for a perimeter of 100. then I plugged these values in the possible equations until I found the correct one giving me an area of 525 (15x35) . I could not think of an easier way.
First we need to find the circumference
C= 2 pi r or C= d*pi
d=2 m
C=2*3.14=6.28
distance traveled=6.28 m*120=753.60 m
Well its a pretty strong wind the answer is 75 mph
First you find out the distance without the wind which is 4x525 or 2,100
Now subtract 1800 from that and you get 300
But you’re still not done because 300 is the number of miles effected by the wind in the whole flight of 4 hours.
So just divide it by 4 and you get 75. So the wind is a 75 mph wind.
Brainliest my answer if it helps you out?
