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Natali5045456 [20]
2 years ago
13

Please answer correctly and no links​

Mathematics
1 answer:
krek1111 [17]2 years ago
4 0

Answer:

-6.825 (-2 33/40). hope this helps

Step-by-step explanation:

- Zombie

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Y=-5x+30

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7 0
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A food production company is choosing between two suppliers of grain. Supplier A sells grain for $5.25 per bushel plus
ANTONII [103]

Answer:

Supplier A: 5.25 per bushel and deliver fee of 3 per bushel

Supplier B: 6.50 per busher and flat delivery fee of $1500 each week

500 bushels of grain each week.

Supplier A: 5.25x + 3x = 5.25(500) + 3(500) =  2,625 + 1,500 = 4,125

Supplier B: 6.50x + 1500 = 6.50(500) + 1500 = 3,250 + 1,500 = 4,750

Supplier B would cost more if the company buys 500 bushels of grain per week.

Step-by-step explanation:

6 0
2 years ago
Solve equation by using the quadratic formula.<br> 6x² – 2x=8
Elenna [48]

Answer:

D

Step-by-step explanation:

6 0
2 years ago
Expand log_1/2(3x^2/2) using the properties and rules for logarithms.<br><br><br> Please help.
Naily [24]

Answer:

\frac{0.1761+2\log(x)}{-0.3010}

Step-by-step explanation:

Data provided:

\log_{1/2}(\frac{3x^2}{2})

now,

we know the properties of log functions as:

1) log(AB) = log(A) + log(B)

2) \log(\frac{A}{B}) = log(A) - log(B)

3) log(xⁿ) = n × log(x)

thus,

\log_{1/2}(\frac{3x^2}{2}) = \log_{1/2}(3x^2) - \log_{1/2}(2)

or

\log_{1/2}(\frac{3x^2}{2}) = \log_{1/2}(3)+\log_{\frac{1}{2}}(x^2) - \log_{1/2}(2)

or

using property 3

\log_{1/2}(\frac{3x^2}{2}) = \log_{1/2}(3)+2\log_{\frac{1}{2}}(x) - \log_{1/2}(2)

also,

\log_a(x)=\frac{\log(x)}{\log(a)}

thus,

\log_{1/2}(\frac{3x^2}{2}) = \frac{\log(3)}{\log(\frac{1}{2})}+2\times[\frac{\log(x)}{\log(\frac{1}{2}}]-\frac{\log(2)}{\log(\frac{1}{2})}

or

\log_{1/2}(\frac{3x^2}{2}) = \frac{\log(3)+2\log(x)-\log(2)}{\log(\frac{1}{2})}

or

\log_{1/2}(\frac{3x^2}{2}) = \frac{\log(3)+2\log(x)-\log(2)}{\log(1)-log(2)}

now,

log(1) = 0

log(2) = 0.3010

log(3) = 0.4771

thus,

\log_{1/2}(\frac{3x^2}{2}) = \frac{0.4771+2\log(x)-0.3010}{0-0.3010}

or

\log_{1/2}(\frac{3x^2}{2}) = \frac{0.1761+2\log(x)}{-0.3010}

6 0
3 years ago
Read 2 more answers
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