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Imagine a new pasture with grass growing on it. Every day after the seeds have germinated, the number of blades of grass in the

Arisa [49]

Answer:

It took 17 days for the pasture to be one-third covered in grass

Step-by-step explanation:

* Lets explain how to solve the problem

- The number of blades of grass is triple every day

- Consider that there are x blades in the first day

∵ The number of blades of grass is triple every day

∴ The next day the number of blades of grass will be 3x

∴ The formula to find the number of blades of grass after d days is

$x(3)^{d}$

- After 18 days, the entire pasture is completely covered in grass

∵ d = 18

∴ The number of blades of grass = $x(3)^{18}$

- We need to know the the number of days that took for the pasture

to be one-third covered in grass

∵ The number of blades of grass for 1/3 covered = $(\frac{1}{3})x(3)^{18}$

∴ $(\frac{1}{3})x(3)^{18}=x(3)^{d}$

- Remember $\frac{1}{3}=3^{-1}$

∴ $3^{-1}x(3)^{18}=x(3)^{d}$

- Remember we add the power of the same bases when we

multiply them

∴ $x(3)^{-1+18}=x(3)^{d}$ ⇒ divide both sides by x

∴ $(3)^{17}=(3)^{d}$

- Remember if the two bases equal in the equation, then their

powers are equal

∴ d = 17

* It took 17 days for the pasture to be one-third covered in grass

4 0

3 years ago

Evaluate the expression 8 + 6 − (8 ÷ 4) x 2 using PEMDAS. 21 17 14 10

Andreyy89

10. 8 divided by 4 is 2 times 2 is 4 8 plus 6 minus 4 is 10

8 0

2 years ago

Read 2 more answers

What is cos theta when sin theta = sqrt 2/3

Fittoniya [83]

Answer:

Value of cosθ is ±√7/3 .

Step-by-step explanation:

According to the Question , value of :

$\red{\implies sin\theta = \dfrac{\sqrt2}{3}}$

And , we know the identity of sine and cosine as ,

$\boxed{\pink{\sf\implies sin^2\theta + cos^2\theta = 1} }$

Using , this identity we have ;

$\implies sin^2\theta + cos^2\theta = 1 \\\\\implies \bigg( \dfrac{\sqrt2}{3}\bigg)^2 + cos^2\theta = 1 \\\\\implies \dfrac{2}{9} + cos^2\theta = 1 \\\\\implies cos^2\theta = 1 - \dfrac{2}{9} \\\\\implies cos^2\theta = \dfrac{9-2}{9} \\\\\implies cos\theta = \sqrt{\dfrac{7}{9}} \\\\\underline{\boxed{\blue{\bf \implies cos\theta = \pm \dfrac{\sqrt 7 }{3}}}}$

Now , here since θ is in 2nd quadrant and in 2nd quadrant cos is negative . Hence ,the value of cos will be :

$\boxed{\orange{\bf \implies cos\theta =-\dfrac{\sqrt7}{3}}}$

3 0

2 years ago

Help me!! Find the area of this figure.

Nezavi [6.7K]

Answer:

510

Step-by-step explanation:

divide into chunks. I divided it like how you would draw the equal sign.

for top chunk, 20*8=160

for 2nd chunk, 8*25=200

for the last chunk, 15*10=150

add up 160, 200, and 150

8 0

3 years ago

Read 2 more answers

Please Fill in the Blank with the simplified equation. 5/8g=40

FinnZ [79.3K]

Multiply both sides by 8

5/8g × 8 = 40× 8

5g = 320

Divide both sides by 5

5g/5 = 320/5

G = 64

4 0

3 years ago