What is the zero of r(x)=8/3x-16?a) -16b) -6c) 6d) 16
2 answers:
we have
![r(x)=\frac{8}{3}x-16](https://tex.z-dn.net/?f=r%28x%29%3D%5Cfrac%7B8%7D%7B3%7Dx-16)
we know that
The zero of the function is the value of x when the function is equal to zero
so
Equate the function r(x) to zero and find the value of x
![\frac{8}{3}x-16=0](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7Dx-16%3D0)
Adds
both sides
![\frac{8}{3}x-16+16=0+16](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7Dx-16%2B16%3D0%2B16)
![\frac{8}{3}x=16](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7Dx%3D16)
Multiply by
both sides
![x=16*\frac{3}{8}\\x=6](https://tex.z-dn.net/?f=x%3D16%2A%5Cfrac%7B3%7D%7B8%7D%5C%5Cx%3D6)
therefore
<u>the answer is the option C</u>
![6](https://tex.z-dn.net/?f=6)
The answer is c, 8/3 (6) - 16 = 0 therefore 6 is the zero
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