You knew where to place the target based on the coordinates (-5,4). Starting from the origin (0,0), we know how many units to move to horizontally and vertically. We move the target 5 units to the left, because it is negative. We move the target 4 units up, because it is positive. (x,y)
Ok <span>One side would have a length of 4, another side would have a length of 5, and then we can use the Pythagorean Theorem to find the length of the hypotenuse. a^2 + b^2 = c^2 </span>
<span>a=4; b=5; </span>
<span>4^2 + 5^2 = c^2 </span>
<span>16 + 25 = c^2 </span>
<span>41 = c^2 </span>
<span>c = √41 </span>
<span>Therefore, the hypotenuse has a length of √41. </span>
<span>To find the sinθ, you take the opposite over the hypotenuse. </span>
<span>Remember when you drew out the triangle? θ is the angle connected to the origin. The opposite side is b, which is 5. </span>
<span>Your answer is 5/√41. </span>
<span>This answer must be simplified since there is a radical in the denominator. To simplify, you can just multiply the numerator and the denominator by √41/√41 (since this is equivalent to 1). </span>
<span>This gives you the answer
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Answer
do u have a demonstration
picture
Step-by-step explanation:
Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so
we have
substitute
therefore
The area of triangle K is 16 times greater than the area of triangle J
We are given the equation y = 2(x – 3)^2 – 4 and is asked for the domain and range of the following function. In this case, there is no radical sign so the domain includes all real numbers. The range has a minimum value of -4 since the squaring makes the value on the first term positive. Hence the answer is A.
