Question

Find the ​slope-intercept form of the equation of the line that passes through the point P and makes angle with the positive ​x-axis

Answer 1

Answer:

The answer is "$y= -x+7$"

Step-by-step explanation:

If $\bold{\theta = 135^{\circ}}$

point: $p=(2,5)$

Formula:

$\to m= \tan \theta \\\\\to (y-y_1)= m(x-x_1)$

$\to m= \tan \ 135^{\circ} = -1\\\\\to x_1= 2\\\\\to y_1=5$

Put the value in the above formula:

$\to y- 5 = -1(x-2)\\\\\to y- 5 = -x+2\\\\\to x+y = 5+2\\\\\to x+y=7$

$\to y= -x+7$