Answer:
11111
Step-by-step explanation:
<em>Multiple of a number is multiplication of the given number with any integer. These integers can be positives as well as negatives. Hence Multiples of any number can either be positive,negative or zero. </em>
According to question,
<u>We need to find a multiple of 41 which contains only 1's.</u>
<em>Hence, we will start by dividing a number greater than 41 which only contains 1's. i.e 111 and keep on adding 1 at unit place until the number is divisible by 41.</em>
111÷41 gives 29 as remainder, hence is not completely divisible by 41.
∴ <u><em>we add 1 to its unit place and use the same process for 1111</em></u>.
1111÷41 is also not divisible by 41 as it leaves 4 as remainder. Hence we add 1 to its unit place and check for 11111.
<u><em>11111÷41=271.</em></u><em> Hence, 11111 is completely divisible by 4</em>1.
∵ <u><em>11111</em></u> is the least number which contains only 1's and is a multiple of 41
