Find the smaller of two consecutive intergers if the sum of the smaller and twice the larger is -4
1 answer:
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The Fundamental Theorem of Calculus regarding geometry states that
Where F is the indefinite integral of
The first step is to integrate
Then substitute the value of
and 
into 
![[2 (b)^{2}]-[2 (1)^{2}] = 240](https://tex.z-dn.net/?f=%5B2%20%28b%29%5E%7B2%7D%5D-%5B2%20%281%29%5E%7B2%7D%5D%20%3D%20240%20)
Hence the limit of the area under is between and
Where F is the indefinite integral of
The first step is to integrate
Then substitute the value of
Hence the limit of the area under
Answer:
Therefore the value of y(1)= 0.9152.
Step-by-step explanation:
According to the Euler's method
y(x+h)≈ y(x) + hy'(x) ....(1)
Given that y(0) =3 and step size (h) = 0.2.
Putting the value of y'(x) in equation (1)
Substituting x =0 and h= 0.2
[∵ y(0) =3 ]
Substituting x =0.2 and h= 0.2
Substituting x =0.4 and h= 0.2
Substituting x =0.6 and h= 0.2
Substituting x =0.8 and h= 0.2
Therefore the value of y(1)= 0.9152.