hello :
<span> y = x2 + 3x -3.... (1)
2x - 1 = y ..........(2)
subsct in (1) :
2x-1 = x² +3x -3
x² + x -2 = 0
(x+2 )(x-1 ) = 0
x+2=0 or x-1 = 0
x=-2 or x=1
if : x = -2 y = 2(-2)-1 =-2
if : x = 1 y = 2(1)-1 = 1
</span><span>values of x will (x, y) be a solution of the system : (-2,-2),(1,1)</span>
Answer:
A. 7776 pi units 3 .......
Answer:
1 5/12 i think im sorry if i get it wrong.
Step-by-step explanation:
Answer:
x = 12
Step-by-step explanation:
Given x varies as the cube root of y then the equation relating them is
x = k![\sqrt[3]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%7D)
← k is the constant of variation
To find k use the condition x = 6 when y = 8, thus
k = ![\frac{x}{\sqrt[3]{y} }](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B%5Csqrt%5B3%5D%7By%7D%20%7D)
= ![\frac{6}{\sqrt[3]{8} }](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B%5Csqrt%5B3%5D%7B8%7D%20%7D)
= 
= 3
x = 3 ← equation of variation
When y = 64, then
x = 3 × ![\sqrt[3]{64}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D)
= 3 × 4 = 12
