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Katen [24]
3 years ago
14

What is the answer to question

Mathematics
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

A

Step-by-step explanation:

I literally don't know how to explain this

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Evaluate 7!.<br> Ο 120<br> Ο 5,040<br> Ο 40,320
timurjin [86]

Answer:

5040 is the answer of it

6 0
3 years ago
A table is 2 feet wide it is 6 times as long it is wide
yan [13]

Answer:

Length = 12 feet

Perimeter = 28 feet

Area = 24ft²

Step-by-step explanation:

You didn't ask a question so I don't know what the answer you want is so I assumed it was related to one of the answers shown above.

To calculate the length, you simply do 6*2

which is equal to 12.  

The length is 12 feet.

However, if you want to find the perimeter:

12 + 12 + 2+ 2 =  28ft

If you wanted to find the area:

12*2 = 24ft²

I hope this helps!

7 0
3 years ago
3 turtles walking.
Elenna [48]

Answer:

Divide 250 by 9.4 to get 26.6

Step-by-step explanation:

To calculate her unit rate, 1 minute, we must divide the distance travelled over 9.4 minutes by 9.4 to see how far she travelled in 1 minute.

8 0
3 years ago
2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi
Oksana_A [137]

Answer:

(a) E(X) = 950

(b) $ COV = 0.007255$

(c) P(X > 980) = 0.00001\\\\

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$ COV = \frac{\sigma}{E(X)} $

Where the standard deviation is given by

\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892

So the coefficient of variance is

$ COV = \frac{6.892}{950} $

$ COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

P(X > 980)  = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980)  = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980)  = 1 - P(Z < 4.28)\\\\

The z-score corresponding to 4.28 is 0.99999

P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0
4 years ago
Add. Write your answers in simplest form.<br><br>10 1/6+12 1/10
Scrat [10]
334/15 also known as 22.26
5 0
4 years ago
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