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myrzilka [38]
3 years ago
5

You use 6 gallons of water on 20 plants in your garden. At that rate, how much water will it take to water 30 plants?

Mathematics
2 answers:
lord [1]3 years ago
8 0
9 because if you divide 6 by 2 you get 3 and if per 10 plants you have to use 3 gallons then for 30 you'll have to use nine because 3x3 equals 9
lana [24]3 years ago
6 0
9 because every ten plants is equal to 3 gallons. 30 plants are equal to 9 gallons.
tell me if if helps.
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4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
Please answer ASAP, I’m really struggling. Percents applications. Mark as brainlest! Write an equation for each problem. Then so
GalinKa [24]

A.

<u>You would leave $30.24 as the tip.</u>

That's a LOT!

B.

<u>The total amount being paid is $178.08.</u>

A total of a $10.08 tax!

C.

<u>You would have spent a total of $208.32.</u>

Yikes!

Hope this helped! If it didn't, please tell me so I can fix it!

7 0
3 years ago
Angle sum theorem y=? Degrees
strojnjashka [21]

Answer:

2x + 70 = 110

x = 20

Step-by-step explanation:

180-110 = 70

70 + 20 + y = 180

y =90

4 0
3 years ago
The area of a rectangular window is 6525cm2. If the length of the window is 87cm, what is its width?
nataly862011 [7]

Answer:

width= 75 cm

Step-by-step explanation:

We need to recall the formula to calculate the area of a rectangle, since we are dealing with a rectangular window:

Area of rectangle = width * length

therefore, since they give us the window's area: 6525 cm^2, and also the window's length: 87 cm, we just need to replace those values in the area formula and solve for the unknown "width". We do such by dividing both sides of the equation by 87 cm in order to isolate the unknown on one side of the equal sign;

6525cm^2 =87cm*width\\\frac{6525cm^2}{87cm} =width\\width=75cm

6 0
3 years ago
which is an equation of the line that is perpendicular to y+1=-3(x-5) and pass through the point (4,-6)
Musya8 [376]

Answer:

Step-by-step explanation:

y+1=-3(x-5)

y + 1 = -3x + 15

     y = -3x  + 15 - 1

     y = -3x + 14

Slope m1 = -3

The required line is perpendicular to this y+1=-3(x-5)

so. m1 * m2 = -1

         -3*m2 = -1

                m2 = -1/-3 = 1/3

Slope = 1/3; pass through (4, -6)

y -y1 = m(x-x1)

y - [-6]  = 1/3 (x - 4)

y + 6   = 1/3 (x - 4)

 y + 6 = 1/3x - 4/3

        y = 1/3x - 4/3 +6      {-4/3 + 6 = -4/3 + 6*3/1*3 =-4/3+18/3 =(-4+18)/3 = 14/3}

         y= 1/3x - 14/3

4 0
3 years ago
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