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NISA [10]
4 years ago
14

What’s the equation equal

Mathematics
2 answers:
Bingel [31]4 years ago
5 0

Answer:

x=0

Step-by-step explanation:

9+5x=9+2x

9+5x-2x=9

9+3x=9

3x=9-9

3x=0

x=0/3

x=0

dexar [7]4 years ago
4 0

Answer:

x = 0

Step-by-step explanation:

Given

9 + 5x = 9 + 2x ( subtract 2x from both sides )

9 + 3x = 9 ( subtract 9 from both sides )

3x = 0 ⇒ x = 0

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Use the rational zero theorem to create a list of all possible rational zeros of the function f(x)=14x7-4x2+2
frosja888 [35]

Answer:

Factor this polynomial:  

F(x)=x^3-x^2-4x+4

Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).  

The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at  

x = 1, x = 2 and x = -2. This means that  

x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)  

A = 1, as you can see from equation the coefficient of x^3 on both sides.  

Typo:  

The rational roots can be  

+/-1, +/-2 and +/-4

Step-by-step explanation:


6 0
3 years ago
Solve the equation 225x^2+4=0
ivann1987 [24]
The answers are 2i/15 and -2i/15. The work is attached below

6 0
3 years ago
Read 2 more answers
Which of the following is a correct interpretation of the expression -7-(-11)
goldenfox [79]

Answer:

(B) Start at -7 on the number line and move 11 to the <em>right.</em>

Step-by-step explanation:

They are negatives, but the -(-11) makes the 11 a positive.

8 0
3 years ago
Describe what you notice when you create the inverse ratio.
Alexeev081 [22]
➜︎Question
Describe what you notice when you create the inverse ratio.

- How do you describe it?

- What do you notice?

- How do you create it?

➜︎Answer
A function composed with its inverse function yields the original starting value. Think of them as "undoing" one another and leaving you right where you started. Basically speaking, the process of finding an inverse is simply the swapping of the x and y coordinates.

- You can describe a inverse ratio by saying how it works

- You can notice the difference

- You could possibly know
6 0
3 years ago
From exterior point L of circle O, tangent segments LP and LQ are drawn such that the measure of angle PLQ is 60 degrees. If a r
IrinaK [193]

Wow !  There's so much extra mush here that the likelihood of being
distracted and led astray is almost unavoidable.

The circle ' O '  is roughly 98.17% (π/3.2) useless to us.  The only reason
we need it at all is in order to recall that the tangent to a circle is
perpendicular to the radius drawn to the tangent point.  And now
we can discard Circle - ' O ' .
Just keep the point at its center, and call it point - O .

-- The segments LP, LQ, and LO, along with the radii OP and OQ, form
two right triangles, reposing romantically hypotenuse-to-hypotenuse. 
The length of segment LO ... their common hypotenuse ... is the answer
to the question.

-- Angle PLQ is 60 degrees.  The common hypotenuse is its bisector.
So the acute angle of each triangle at point ' L ' is 30 degrees, and the
acute angle of each triangle at point ' O ' is 60 degrees.

-- The leg of each triangle opposite the 30-degree angle is a radius
of the discarded circle, and measures 6 .

-- In every 30-60 right triangle, the length of the side opposite the hypotenuse
is  one-half the length of the hypotenuse.

-- So the length of the hypotenuse (segment LO) is  <em>12 </em>.


4 0
4 years ago
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