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Lapatulllka [165]
3 years ago
9

3.

Mathematics
1 answer:
madam [21]3 years ago
3 0

Answer:

24 cups

Step-by-step explanation:

Peaches to Cherries is given as 2 to 3

We can think of this as "parts". So total parts in the salad would be:

Total Part = 2 + 3 = 5 parts

So, now we need cups of peaches to cups of TOTAL

The ratio would be:

2 : 5

The total would be 60 cups

We let total cup of peaches be x

So we can write the ratio:

\frac{2}{5}=\frac{x}{60}

Now, we cross multiply and solve for x:

\frac{2}{5}=\frac{x}{60}\\5x=2*60\\5x=120\\x=24

Fred will need 24 cups of peaches

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Lacy draws a diamond from a standard deck of 52 cards. Without replacing the first card, she then proceeds to draw a second card
Viktor [21]

Answer:

a) i) No

ii) Probability of drawing a diamond and then spade without replacement is 0.0637.

b) i) Yes

ii) Probability of drawing a diamond and then spade with replacement is 0.0625

Step-by-step explanation:

Part a) Without replacement:

i) Are these events independent?

No, because the both events are dependent. because a card taken out of the deck is not replaced back before taking out the other card so the chances of event occur change.

ii) Determine the probability of drawing a diamond and then a spade without replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after taking diamond = 52 -1 =51

Spades = 13

Probability of drawing a spade  = 13/51

Probability of drawing a diamond and then spade = 13/52 * 13/51

= 169/2652

=0.0637

So, Probability of drawing a diamond and then spade without replacement  is 0.0637

Part b) With replacements

i) Are these events independent?

Input Yes or No:

Yes, these events are independent because a card taken out of the deck is replaced back before taking out the other card so the chances of event occur doesn't change.

ii) Determine the probability of drawing a diamond and then a spade with replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after replacing diamond = 52

Spades = 13

Probability of drawing a spade  = 13/52

Probability of drawing a diamond and then spade = 13/52 * 13/52

= 169/2704

=0.0625

So, Probability of drawing a diamond and then spade with replacement is 0.0625

7 0
4 years ago
Find, explain, and correct the error in the student work below.
Artemon [7]
The correct answer is 0
6 0
3 years ago
What is 9 3/12 + 6 2/3
BartSMP [9]

Answer:

191/12

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please help and show how you got the answer:
kari74 [83]

4 - 6n = 60 - 2n   <em>subtract 4 from both sides</em>

-6n = 56 - 2n    <em>add 2n to both sides</em>

-4n = 56    <em>divide both sides by (-4)</em>

n = - 14


-7 + 11p = 3p - 47       <em>add 7 to both sides</em>

11p = 3p - 40      <em>subtract 3p from both sides</em>

8p = -40      <em>divide both sides by 8</em>

p = - 5


3a - 28 - 7a = 10a          <em>combine like terms</em>

(3a - 7a) - 28 = 10a

-4a - 28 = 10a       <em>add 28 to both sides</em>

-4a = 10a + 28       <em>subtract 10 from both sides</em>

-14a = 28     <em>divide both sides by (-14)</em>

a = - 2


17 - 5r + 9r = 12 + 6r - 1       <em>combine like terms</em>

17 + (-5r + 9r) = (12 - 1) + 6r

17 + 4r = 11 + 6r      <em>subtract 17 from both sides</em>

4r = -6 + 6r     <em>subtract 6r from both sides</em>

-2r = -6      <em>divide both sides by (-2)</em>

r = 3


8(y - 7) = -2(y + 3)    <em>use distributive property: a(b + c) = ab + ac</em>

(8)(y) + (8)(-7) = (-2)(y) + (-2)(3)

8y - 56 = -2y - 6       <em>add 56 to both sides</em>

8y = -2y + 50     <em>add 2y to both sides</em>

10y = 50    <em>divide both sides by 10</em>

y = 5


-3(8k + 5) = 3(9 - k)      <em>use distributive property: a(b + c) = ab + ac</em>

(-3)(8k) + (-3)(5) = (3)(9) + (3)(-k)

-24k - 15 = 27 - 3k      <em>add 15 to both sides</em>

-24k = 42 - 3k      <em>add 3k to both sides</em>

-21k = 42     <em>divide both sides by (-21)</em>

k = -2


2(3v - 5) = 2(v - 11) - 4   <em>use distributive property: a(b + c) = ab + ac</em>

(2)(3v) + (2)(-5) = (2)(v) + (2)(-11) - 4

6v - 10 = 2v - 22 - 4

6v - 10 = 2v - 26      <em>add 10 to both sides</em>

6v = 2v - 16      <em>subtract 2v from both sides</em>

4v = -16      <em>divide both sides by 4</em>

v = -4


-2/3 (15x + 3) -3x - 9    <em>use distributive property: a(b + c) = ab + ac</em>

= (-2/3)(15x) + (-2/3)(3) - 3x - 9

= (-2)(5x) - 2 - 3x - 9

= -10x - 2 - 3x - 9                 <em>combine like terms</em>

= (-10x - 3x) + (-2 - 9)

= -13x - 11


3(1 - 9a) + 22a = 2(2a - 9) - 15

<em>use distributive property: a(b + c) = ab + ac</em>

(3)(1) + (3)(-9a) + 22a = (2)(2a) + (2)(-9) - 15

3 - 27a + 22a = 4a - 18 - 15          <em>combine like terms</em>

3 + (-27a + 22a) = 4a + (-18 - 15)

3 - 5a = 4a - 33      <em>subtract 3 from both sides</em>

-5a = 4a - 36       <em>subtract 4a from both sides</em>

-9a = -36      <em>divide both sides by (-9)</em>

a = 4


-3(3m - 10) - 7 = -5(m + 1) + 3m

<em>use distributive property: a(b + c) = ab + ac</em>

(-3)(3m) + (-3)(-10) - 7 = (-5)(m) + (-5)(1) + 3m

-9m + 30 - 7 = -5m - 5 + 3m           <em>combine like terms</em>

-9m + (30 - 7) = (-5m + 3m) - 5

-9m + 23 = -2m - 5     <em>subtract 23 from both sides</em>

-9m = -2m - 28        <em>add 2m to both sides</em>

-7m = -28      <em>divide both sides by (-7)</em>

m = 4

6 0
3 years ago
What did the Egyptians believe about spirits? What role did they believe that the Gods played in their world?
Natasha_Volkova [10]

Answer:

I only know the first one well. I don't want to answer the others and maybe give false info.

Step-by-step explanation:

Egyptians were very well known to be very interested in Spirits and Gods.

Their whole dynasty was built on the dawn of their Gods. There were many, like the Greek and Roman Gods. One of the sun, one of the underworld....etc..

The pharaohs believed themselves to be god. (Due to their immense power)

Egyptians believed that after death there was an Afterlife. In that afterlife, there was games, other people (spirits), homes (graves). This might sound weird but in the graves especially of Pharaohs they placed beds, tables, chairs, games..etc..

<h3>Hope this Helps!</h3>

:)

6 0
3 years ago
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