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BaLLatris [955]
3 years ago
6

Find the surface area of the pyramid

Mathematics
2 answers:
polet [3.4K]3 years ago
7 0
It would be 156 because if you do the math you will get that 10*6 60/2 to get 30*4+36 equals 156
34kurt3 years ago
6 0

Answer:

The surface is 156

Step-by-step explanation:

The bottom is 36, and the triangles are 30 each, 30x4=120, 120+36=156

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Plz help mee with thisss
timurjin [86]

Answer:

495

Step-by-step explanation:

60x10=600

600-105=495

3 0
3 years ago
The product of two numbers is 48, and one of the numbers is 12. Find the other number.
Vladimir79 [104]

Answer:

i believe the answer is b

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Covert 9.46×^10-6 into regular notation
weqwewe [10]

Answer:

0.00000946

Step-by-step explanation:

9.46×^10⁻⁶ =0.00000946

<u>Trick:</u>

Since the exponent of the scientific notation is negative, move the decimal point 6 places to the left

5 0
3 years ago
What is the value of x? 6x - 2x = 16
agasfer [191]

6x - 2x = 16

4x = 16    |divide both sides by 4

<h3>x = 4</h3>
5 0
3 years ago
Read 2 more answers
Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets for a flight that holds only 12
melamori03 [73]

Answer:

98.75% probability that every passenger who shows up can take the flight

Step-by-step explanation:

For each passenger who show up, there are only two possible outcomes. Either they can take the flight, or they do not. The probability of a passenger taking the flight is independent from other passenger. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

The probability that a passenger does not show up is 0.10:

This means that the probability of showing up is 1-0.1 = 0.9. So p = 0.9

Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets

This means that n = 125

Using the approximation:

\mu = E(X) = np = 125*0.9 = 112.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{125*0.9*0.1} = 3.354

(a) What is the probability that every passenger who shows up can take the flight

This is P(X \leq 120), so this is the pvalue of Z when X = 120.

Z = \frac{X - \mu}{\sigma}

Z = \frac{120 - 112.5}{3.354}

Z = 2.24

Z = 2.24 has a pvalue of 0.9875

98.75% probability that every passenger who shows up can take the flight

7 0
3 years ago
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