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kati45 [8]
3 years ago
14

Find the circumference of the given circle. Use 3.14 for pi, and round your answer to the nearest tenth.

Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer:

Sorry, I can't complete this without knowing the radius, or diameter.

Step-by-step explanation:

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The graphs below have the same shape. What is the equation of the blue<br>graph?​
Semenov [28]

Answer:

the answer is d

Step-by-step explanation:

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

vertex- (5,0)

focus- (5,1/4)

axis of symmetry-  x=5

directrix- y=-1/4

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5 0
3 years ago
Mr. Rob has 8 blue, 5 grey, 6 black, and 3 red ties. What is the ratio of blue ties to all of Mr. Rob's ties.
Nataly [62]

Answer:

8 blue ties to 21 ties (8/21

Step-by-step explanation:

You take the amount of blue ties and the put them over the total amount of ties (Blue + Grey + Black + Red)

5 0
2 years ago
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Factorize: x² + 3x + 2​
zvonat [6]

Step-by-step explanation:

x² + 3x + 2

x² + x + 2x + 2 because 1+2=3 and 2×1=2

By taking out common terms, we get

x(x+1)+2(x+1)

(x+1)(x+2)

7 0
3 years ago
What is the distance between 182 and 265 on a number line?
lawyer [7]
The correct answer is B. 83
5 0
3 years ago
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Write the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5)
Sedbober [7]

Answer:   \bold{y=-\dfrac{1}{3}x-1}

<u>Step-by-step explanation:</u>

(4, 1) & (2, -5)

First, find the slope (m) and then the perpendicular (opposite reciprocal) slope:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\\m=\dfrac{-5-1}{2-4} = \dfrac{-6}{-2}=3\quad \rightarrow \quad m_{\perp}=-\dfrac{1}{3}\\

Next, find the midpoint of (4, 1) and (2, -5):

Midpoint=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{4+2}{2},\dfrac{1-5}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{6}{2},\dfrac{-4}{2}\bigg)\\\\\\.\qquad \qquad=(3, -2)

Lastly, input the perpendicular slope and the midpoint into the Point-Slope formula to find the equation of the line:

y - y_1 = m_{\perp}(x - x_1)\\\\y - (-2) = -\dfrac{1}{3}(x - 3)\\\\y + 2=-\dfrac{1}{3}x +1\\\\y =-\dfrac{1}{3}x - 1\\


6 0
3 years ago
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