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JulijaS [17]
3 years ago
5

What is c- 1/2 + 16=36

Mathematics
2 answers:
aleksley [76]3 years ago
7 0

Answer:

c=20.5 or 41/2

Step-by-step explanation:

c- 1/2 + 16=36

Make C the subject

c=36-16+1/2

c=20+1/2

Using LCM

c=(40+1)/2

c=41/2

c=20.5

To check if we are correct, we substitute c with 41/2. and then both sides of the equation must be equal

c- 1/2 + 16=36

41/2-1/2+16=36

20+16=36

36=36

sasho [114]3 years ago
4 0

Answer:

20 1/2

Step-by-step explanation:

its 20 and a half because 16+20=36 and you just need to add a half to 20 since your taking it away

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27^{3x}=(1/9)^x<br> write in b^x=b^y form
iogann1982 [59]

Answer:

3^9x=3^-2x

Step-by-step explanation:

27^3x=(1/9)^x

3^3×3x=(1/3^2)^x

3^9x=3^-2x

5 0
3 years ago
Find the population mean or sample mean as indicated. Sample: 19, 15, 6, 11, 24 Compute the sample mean for this data set. Selec
yKpoI14uk [10]

Answer:

\overline{x}=15

Step-by-step explanation:

the mean is given by:

\overline{x} = \dfrac{\sum\limits_{i=1}^n x_i}{n} \quad\text{or}\quad \dfrac{\text{sum of all items}}{\text{number of items}}

In our case this is:

\overline{x} = \dfrac{19+15+6+11+24}{5} \Rightarrow \dfrac{75}{5}\\\\\overline{x} = 15\\\\

side note: the main difference between sample mean and population mean is in the 'context'. However, the method to calculate them is the same.

By context I mean: if this the items are taken from some larger category for example: the ages of a few 'students' from a 'class'. Here 'students' are the sample from a larger set that is 'class'. The mean of the 'few students' will be called sample mean. In contrast, if we take the mean of the ages of the whole class then this is called population mean. (population mean == mean of the whole set)

In our case we aren't told exactly where these numbers come from, is this the whole set or a sample from it, the lack of context allows us to assume that the mean can either be population mean or sample mean. So we can safely use any symbol \mu or \overline{x}.

3 0
3 years ago
A researcher was testing the number of popcorn kernels that popped out of a mini bag of 100 kernels after being cooked for the s
Lelechka [254]

Answer:

The percentage of the bag that should have popped 96 kernels or more is 2.1%.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.

The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.

Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.

Compute the probability that a bag popped 96 kernels or more as follows:

Apply continuity correction:

P( X\geq 96)=P( X>96+0.50)

                 =P( X>96.50)\\=P(\frac{X-\mu}{\sigma}>\frac{96.50-72}{12})\\=P(Z>2.04)\\=1-P(Z

*Use a <em>z</em>-table.

The probability that a bag popped 96 kernels or more is 0.021.

The percentage is, 0.021 × 100 = 2.1%.

Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.

3 0
3 years ago
What is the answer to -26-(-49)?
Radda [10]

Answer:

23

Step-by-step explanation:

-26-(-49)=-26+49=23

7 0
3 years ago
Read 2 more answers
The sum of the square root of a number and 6
Anna007 [38]

Answer:

36

Step-by-step explanation:

4 0
3 years ago
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