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velikii [3]
3 years ago
11

Which one is not an operating system?1.mac 2.Microsoft office3.Iso.3.Android

Computers and Technology
1 answer:
quester [9]3 years ago
6 0
It's either microsoft or office. Based on research I would say office.

I really hope this helps you! :-)
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Consider a set of mobile computing clients in a certain town who each
poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0
3 years ago
The collection of computer instructions and other files that constitute a piece of software is
lutik1710 [3]
The answer would be
A. Codebase

8 0
3 years ago
Read 2 more answers
The following code does not work as intended. It is meant to input two test grades and return the average in decimal format:
vredina [299]

Answer:

Type casting error

Explanation:

Logically, the program is correct and it is expected to return the average value. However, test1 and test2 are int values and when you applies any algebraic expression on Int, it will result into Int.

So, in this part (test1 + test2 )/2, two integers are adding and the final result is still an integer and this part will act as an integer even if you multiple or divide with any external number.

For example,

test1 = 4

test2 = 5

test1 + test2 = 9

Now, if you divide it by 2, it will still react as an integer portion. So, 9/2 would result in 4 instead of 4.5. All the calculation is done on the right side before assigning it to a double variable. Therefore, the double variable is still getting the int value and your program is not working correctly.

The solution is to typecast the "(test1 + test2 )/2" portion to double using Double.valueOf(test1 + test2)/2 ;

I have also attached the working code below.

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 System.out.println("Hello World");

 Scanner scan = new Scanner (System.in);

 int test1 = scan.nextInt();

       int test2 = scan.nextInt();

       double average = Double.valueOf(test1 + test2)/2 ;

       System.out.println("Answer: " + average);

}

}

4 0
3 years ago
Let's now use our new calculator functions to do some calculations!
Sophie [7]

Answer:

Ans1.

double calc_a;

calc_a=Math.pow(3.0,2.0)+Math.sqrt(9);

Ans2.

double calc_b;

calc_b=((12.0/3.0)-(2.0*4.0));

Ans 3.

double calc_c;

calc_c=(Math.sqrt(16.0)*(7.0+9.0));

Ans 4.

double calc_d;

calc_d=Math.pow(7.0,2.0)/Math.sqrt(49.0);

Explanation:

The expressions are done with Java in answer above.

6 0
3 years ago
AP CSA help needed. Java please.
leva [86]
#include using namespace std;int main(){int year = 12,value = 10,total = 0;do{year++;value *= 2;total += value;}while(value*2 < 1000);cout << "Age: " << year << endl;cout << "Last gift: " << value << endl;cout << "Total: " << total << endl;cin.get();return 0;
5 0
2 years ago
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