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goblinko [34]
3 years ago
7

A company needs $5,400,000 in 14 years in order to expand their factory. How much should the company invest each week if the inv

estment earns a rate of 7.9% compounded weekly?
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer: the company should invest $12191 each week

Step-by-step explanation:

The amount that the company needs is $5,400,000

We would apply the periodic interest rate formula which is expressed as

P = a/[{(1+r)^n]-1}/{r(1+r)^n}]

Where

P represents the weekly payments.

a represents the amount that the company needs

r represents the rate.

n represents number of weekly payments. Therefore

a = 5,400000

There are 52 weeks in a year

r = 0.079/52 = 0.0015

n = 52 × 14 = 728

Therefore,

P = 5400000/[{(1+0.0015)^728]-1}/{0.0015(1+0.0015)^728}]

5400000/[{(1.0015)^728]-1}/{0.0015(1.0015)^728}]

P = 5400000/{2.98 -1}/[0.0015(2.98)]

P = 5400000/(1.98/0.00447)

P = 5400000/442.95

P = $12191

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3 years ago
550 tickets were sold for a game for a total of $712.50. If adult tickets sold for $1.50 and children's tickets sold for $1.00,
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Answer:

  • adult: 325
  • children's: 225

Step-by-step explanation:

It usually works well to let a variable represent the higher-value item in the mix. Here, we can let 'a' represent the number of adult tickets sold. Then the total revenue is ...

  1.50a +1.00(550 -a) = 712.50

  0.50a = 162.50 . . . . . . . . . . . . . subtract 550 and collect terms

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  c = 550 -325 = 225

325 adult and 225 children's tickets were sold.

4 0
3 years ago
What two factors multiply to -90 add up to 27
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30 and -3

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30 x -3=-90

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7 0
3 years ago
Mari and Jen each work 20 hours a week at different jobs. Mari earns twice as much as Jen. Together they earn $480. How much doe
Salsk061 [2.6K]
We will call:
M=Mari
J=Jen

Initial equations:

M=2J
M+J=480
(the fact that they work 20 hours a week is not needed in this problem information)

Plug in:
2J+J=480
3J=480
J=160

Jen makes $160 a week.

Therefore:

M=2J
M=2(160)
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Mari makes $320 per week
Jen makes $160 per week
7 0
3 years ago
You purchase 26 parking hours that you can use the next month to park your food truck at the fair. Weekday hours park $2 per hou
ICE Princess25 [194]

Answer:

Number of week day hours purchased  is 5

Step-by-step explanation:

Total number of Parking hours purchased = 26 parking hours

Parking cost on weekdays = $2 per hour

Parking costs on weekends = $10 per hour

Total amount spent on parking =  $220.

To Find:

Number of week days purchased = ?

Solution:

Let  

The number of week days purchased be x

The number of weekends purchased be  y

We know that the total hours purchased is 26

So,

x+y = 26

y = 26-x------------------------------------------------------(1)

Now the total cost is 220

(Total number of weekdays X cost per weekday ) +(Total number of weekends + cost per weekend) =220

Substituting the values

=>x\times 2 + y \times 10 = 220

=>x \times 2 + (26-x) \times 10 =220

=>2x + 260 -10x =220

=>260 -8x = 220

=>260 -220 =8x

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=>x=\frac{40}{8}

x= 5-------------------------------------------(2)

Now substituting (2) in (1) we get

y= 26-5

y= 21

7 0
4 years ago
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