Write in standard form a)0.00000678 b)3170000
1 answer:
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Given:
and,
K = 1
We would require to do the synthetic division of the above problem in order to know whether K=1 is a lower bound or not. Let's do it!
Steps of Synthetic Division:
1. Write the coefficients of the equation, and before that write 1. Like,
1 ║ 4 -2 2 4
As you can see, the coefficients of the equation are seperated by ║.
2. Drop down the first value after ║as it is. Like:
1 ║ 4 -2 2 4
:
----------------------
4
3. Multiply 4 with 1 and then place the resultant value under -2 and then add that resultant value with -2. Like
1 ║ 4 -2 2 4
: 4
----------------------
4 2
4. Repeat Step 3 until you're done.
1 ║ 4 -2 2 4
: 4 2
----------------------
4 2 4
1 ║ 4 -2 2 4
: 4 2 4
----------------------
4 2 4 8
Now every value, +4, +2, +4, +8, under the bar(---------) is positive; therefore, it means that K=1 is the upper bound, NOT lower bound.
Ans: K=1 is NOT a lower bound.
-i
and,
K = 1
We would require to do the synthetic division of the above problem in order to know whether K=1 is a lower bound or not. Let's do it!
Steps of Synthetic Division:
1. Write the coefficients of the equation, and before that write 1. Like,
1 ║ 4 -2 2 4
As you can see, the coefficients of the equation are seperated by ║.
2. Drop down the first value after ║as it is. Like:
1 ║ 4 -2 2 4
:
----------------------
4
3. Multiply 4 with 1 and then place the resultant value under -2 and then add that resultant value with -2. Like
1 ║ 4 -2 2 4
: 4
----------------------
4 2
4. Repeat Step 3 until you're done.
1 ║ 4 -2 2 4
: 4 2
----------------------
4 2 4
1 ║ 4 -2 2 4
: 4 2 4
----------------------
4 2 4 8
Now every value, +4, +2, +4, +8, under the bar(---------) is positive; therefore, it means that K=1 is the upper bound, NOT lower bound.
Ans: K=1 is NOT a lower bound.
-i
In geometry, it is always advantageous to draw a diagram from the given information in order to visualize the problem in the context of the given.
A figure has been drawn to define the vertices and intersections.
The given lengths are also noted.
From the properties of a kite, the diagonals intersect at right angles, resulting in four right triangles.
Since we know two of the sides of each of the right triangles, we can calculate their heights which in turn are the segments which make up the other diagonal.
From triangle A F G, we use Pythagoras theorem to find
h1=A F=sqrt(20*20-12*12)=sqrt(256)=16
From triangle DFG, we use Pythagoras theorem to find
h2=DF=sqrt(13*13-12*12)=sqrt(25) = 5
So the length of the other diagonal equals 16+5=21 cm
