1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RSB [31]
3 years ago
10

The mass of a teapot and 4 cups is 1,280 grams. The mass of the same teapot and 10 cups is 2,720 grams. Each cup has the same ma

ss. What is the mass of the teapot?
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer: 320 grams

Step-by-step explanation:

Let the mas of the teapot be denoted by a

Let the mass of the cups be denoted by c

The question can be turned into an equation which will be:

a + 4c = 1280 ......... equation i

a + 10c = 2720 ........ equation ii

Subtract equation i from ii

6c = 1440

c = 1440/6

c = 240 grams

The mas of the cup is 240 grams

From equation i

a + 4c = 1280

a + 4(240) = 1280

a + 960 = 1280

a = 1280 - 960

a = 320 grams

The mass of the teapot is 320 grams

You might be interested in
Which parent function is graphed below
aleksandrvk [35]

Answer:

the answer for this question is c because that is the answer

4 0
3 years ago
If G = {(-1, 7),(-8, 2),(0, 0),(6, 6)), then the range of G is
lana66690 [7]

Answer:

\{0, 2, 6, 7\}

Step-by-step explanation:

You are given the relation G = \{(-1, 7),(-8, 2),(0, 0),(6, 6)\}

This means that

f(-1)=7\\ f(-8)=0\\f(0)=0\\f(6)=6

The input values of this relation are -1,\ -8,\ 0,\ 6, so the domain of this relation is \{-8,-1,0,6\}

The output values of this relation are 7,\ 2,\ 0,\ 6, so the range of this relation is \{0, 2, 6, 7\}

8 0
3 years ago
In measuring the center of the data from a skewed distribution, the median would be preferred over the mean for most purposes be
icang [17]
<span>The median would be preferred over the mean in such scenarios because the median will lessen the impact of the outliers that fall within the "tail" of the skew. Therefore, if a curve is normally distributed, that is to say that data is normally distributed, there will be two tails, each with approximately equal proportions of outliers. Outliers in this case being more extreme numbers, and are based on your determination depending on how you are using the data. If data is skewed there is one tail, and therefore it may be an inaccurate measure of central tendency if you use the mean of the numbers. Thinking of this visually. In positively skewed data where there is a "tail" towards the right and a "peak" towards the left, the median will be placed more in the "peak", whereas the mean will be placed more towards the "tail", making it a poorer measure of central tendency, or the center of the data.</span>
5 0
3 years ago
What is the value of f(x) when x =0
kobusy [5.1K]

Answer:

-1, 2 and 4

Step-by-step explanation:

6 0
3 years ago
WILL BE GIVING BRAINLIEST, 5 STARS, AND THANKS WITHIN AN HOUR.
pantera1 [17]
39.5 i am pretty suree of it :P
4 0
3 years ago
Other questions:
  • Gina opened a bank account with $40. She plans to add $20 per week to the account and not make any withdrawals. After how many w
    8·1 answer
  • 32% of an amount of money is $200. What is the total amount?
    9·2 answers
  • An eight-month used stereo system was sold for $255.75. This was one third (1/3) the amount of what this system originally cost.
    11·1 answer
  • 10 watermelon coat $15.What is the cost of one watermelon?
    11·1 answer
  • Evaluate the expression |2x – 5| for x = –3 and for x = 3.
    10·1 answer
  • You roll a number cube 2 times how many outcomes are possible
    11·2 answers
  • write the first five terms of the sequence defined by the recursive formula an = 2 (an-1)^2, with a1 = 1.
    7·1 answer
  • Need ASAP please help me
    11·2 answers
  • Tell whether x and y are proportional.
    13·1 answer
  • Phillip claimed that the expression − p + 5 + p is positive for any value of p. Determine whether Phillip’s statement is always
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!