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Shalnov [3]
2 years ago
10

(Pls add an image of the area model and ill give brainliest!! :D)

Mathematics
1 answer:
eimsori [14]2 years ago
6 0

7436 ÷ 13 = 572

I didn't understand the rest of the thing u mentioned

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IgorLugansk [536]

Answer:

1. 144 : 16 = 9

2. 13.5 x 17 = 229.5

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3 years ago
What is the value of the expression x + (–y) when x = –2.3 and y = –5.9? A. –8.2 B. –3.6 C. 3.6 D. 8.2
11Alexandr11 [23.1K]
Now it would be
-2.3+(-5.9)

now just add those two together
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Find the value of X?
daser333 [38]
Because we know the midpoint is in the middle, we know that both sides are equal.
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3 0
3 years ago
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A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square
kondaur [170]
This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

V = xxy = x^{2}y

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = x^{2}

Surface area of the rectangular sides = 4xy

Therefore, the total area of the cube is:

A = 48 ft^{2} =  x^{2} + 4xy

Isolating the variable y in terms of x:

y =  \frac{48- x^{2} }{4x}

Substituting this value in V:

V =  x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

\frac{dv}{dx} = 48-3x^{2} =0

Solving for x:

x =  \sqrt{\frac{48}{3}} =  \sqrt{16} = 4

Solving for y:

y =  \frac{48- 4^{2} }{(4)(4)} = 2

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width =  4 ft
Height = 2 ft

And its volume is:

V = (4^{2} )(2) = 32 ft^{3}

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3 years ago
The school principal wants to order 2 pencils for the 425 students in the school. How many boxes should she order?
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How many pencils are in each box
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