The domain of this function is x = all real numbers.
The range of this function is that y ≥ 0.
To find the domain, you need to look for exclusions. The only numbers that you exclude are when you can't divide by 0 or have a negative square root. Since this problem has no square root symbol or fractions, it is all real numbers.
For the range, we need to find the smallest value of y. y can get no smaller in this problem than when x = 0. In that case y also = 0. Because the lead coefficient is positive (4), we know that the graph is increasing. Therefore, we know that y must always be bigger than 0.
Answer:
please give more information
Step-by-step explanation:
Answer:
A = 72, P = 38
Step-by-step explanation:
Area can be found by getting the area of the overall figure, and then subtracting the blank space in the corner
12 * 7 = 84
3 * 4 = 12(invisible rectangle in top right)
84 - 12 = 72
Perimeter can be found by adding all of the sides
12 + 7 + (12-4) + 3 + 4 + (7-4)
The numbers in brackets are the unlabeled sides on the top and left.
The perimeter of a semicircle consists of two parts. (the curve and bottom)
That curve is half the distance around the circle, since it's been split in half.
The distance around a circle, the circumfrence, is equal to 2πr, where r is the radius of that circle. In this case, the circumfrence of the entire circle would be 16π. and so that curve would have a length of just 8π.
Using 3.14 for π, 8π = 8×3.14 = 25.12.
As for the flat part, that is the diameter (distance across) our circle.
The radius is the distance from the center of a circle to its edge, and always has half the length of the diameter. (you can break the diameter down into two radii)
If our radius is 8 meters, our diameter (the flat part of that semicircle) must be 16.
Now we add up the two parts of the perimeter...25.12 + 16 = 41.12.
Answer:
The value of the equation 
.
Step-by-step explanation:
Consider the provided equation.
We need to solve the provided equation for y.
Subtract 3x from both side.
Divide both sides by 7.
Hence, the value of the equation is .
