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Roman55 [17]
4 years ago
5

Use zero- through third-order taylor series expansions to predict f(3) for f (x) = 25x3 − 6x2 + 7x − 88 using a base point at x

= 1. compute the true percent relative error εt for each approximatio

Mathematics
1 answer:
nexus9112 [7]4 years ago
7 0

Hello from MrBillDoesMath!

See attachment for Details

Answer:

f(3) = 554, with no error

Thank you,

MrB

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What is the equation of the following line written in slope-intercept form?
nasty-shy [4]
SOLUTION:

To begin with, let's establish that the formula of this line is in slope-intercept form as follows:

y = mx

The formula for this line isn't:

y = mx + b

This is as this line doesn't have a y-intercept ( b ) as it passes through the origin instead. This means that ( b ) would be rendered useless in this formula as it would just bring us back to the y = mx formula as displayed below:

y = mx + b
y = mx + 0
y = mx

Moving on, for ( m ), we need to find the gradient of the line as displayed below:

m = gradient
m = rise / run
m = 10 / 2
m = 5

Now, we must simply substitue ( m ) into the formula in order to obtain the equation for this line as displayed below:

y = mx
y = 5x

Therefore, the answer is:

A. y = 5x
6 0
3 years ago
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Vitek1552 [10]

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2. 8x

3. (12/2)*(10/2)

Step-by-step explanation:

4 0
3 years ago
The amount left over after dividing two numbers is the
QveST [7]

Answer: integer division, or remainder

Step-by-step explanation:

6 0
4 years ago
V(t), left parenthesis, t, right parenthesis models the number of visitors in a park as a function of the outside temperature t
Kruka [31]

Answer:

The number of visitors increases at the same rate over both intervals

Step-by-step explanation:

The unit rate at which the number of visitors in the park increases over a given temperature interval is called the average rate of change, or ARCARCA, R, C.

To find the average rate of change of a function over an interval, we need to take the total change in the function value over the interval and divide it by the length of the interval.

Hint #22 / 3

We are asked to compare the rates at which the number of visitors increases over the interval between an outside temperature of 181818 degrees Celsius and 202020 degrees Celsius, and over the interval between an outside temperature of 202020 degrees Celsius and 272727 degrees Celsius. These correspond to the domain intervals [18,20][18,20]open bracket, 18, comma, 20, close bracket and [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Let's calculate the average rate of change of VVV over those intervals:

ARC_{[18,20]}ARC

[18,20]

​

A, R, C, start subscript, open bracket, 18, comma, 20, close bracket, end subscript ARC_{[20,27]}ARC

[20,27]

​

A, R, C, start subscript, open bracket, 20, comma, 27, close bracket, end subscript

\begin{aligned} \dfrac{V(20)-V(18)}{20-18}&=\dfrac{18-10}{2}\\\\&=\dfrac{8}{2}\\\\&=4\end{aligned}\quad

20−18

V(20)−V(18)

​

​

 

=

2

18−10

​

=

2

8

​

=4

​

 \begin{aligned} \dfrac{V(27)-V(20)}{27-20}&=\dfrac{46-18}{7}\\\\&=\dfrac{28}{7}\\\\&=4\end{aligned}

27−20

V(27)−V(20)

​

​

 

=

7

46−18

​

=

7

28

​

=4

​

Hint #33 / 3

The average rate of change over the interval [18,20][18,20]open bracket, 18, comma, 20, close bracket is the same as the average rate of change over the interval [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Therefore, the number of visitors increases at the same rate over both intervals.

7 0
3 years ago
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